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mylen [45]
2 years ago
12

+10 points~~~Which option is used in emails to inform the recipient that they should exercise discretion in accordance with shar

ing the content of the message?
priority levels
sensitivity levels
follow-up flags
attachment icons
Computers and Technology
1 answer:
Alexxx [7]2 years ago
8 0

Answer:

Sensitivity Levels

Explanation:

Sensitivity Level is option use in email to inform the recipient that they should exercise discretion in accordance with sharing the content of the message.

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Writing in Java, write a program that prompts the user to input an integer and then outputs both the individual digits of the nu
larisa [96]

Answer:

//Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

       int in;

     //scanner class object to read the input

    Scanner scr=new Scanner(System.in);

     // variable to keep running total

    int total=0;

    System.out.println("please enter an Integer:");

     // read the input first time

    in=scr.nextInt();

    System.out.print("individual digits of "+in+" is ");

    if(in<0)

    {

        in=-(in);

    }

   

 

     //call the function to print the digits of number

   print_dig(in);

   System.out.println();

    //calculate the sum of all digits

   do{

       int r=in%10;

       total=total+r;

       in=in/10;

   }while(in>0);

    //print the sum

   System.out.println("total of digits is: "+total);

     

   }catch(Exception ex){

       return;}

}

 //recursive function to print the digits of number

public static void print_dig(int num)

{  

    if(num==0)

    return;

    else

    {

    print_dig(num/10);

    System.out.print(num%10+" ");

    }

}

}

Explanation:

Read a number with the help of object of scanner class.if the input is negative

then make it positive number before calling the function print_dig().call

the recursive method print_dig() with parameter "num".It will extract the digits

of the number and print then in the order. Then in the main method, calculate

sum of all the digits of number.

Output:

please enter an Integer:                                                                                                  

3456                                                                                                                      

individual digits of 3456 is 3 4 5 6                                                                                      

total of digits is: 18

please enter an Integer:                                                                                                  

-2345                                                                                                                      

individual digits of -2345 is 2 3 4 5                                                                                      

total of digits is: 14

6 0
2 years ago
Import java.util.scanner; public class sumofmax { public double findmax(double num1, double num2) { double maxval; // note: if-e
jeyben [28]

Here you go,


Import java.util.scanner

public class SumOfMax {

   public static double findMax(double num1, double num2) {

       double maxVal = 0.0;

       // Note: if-else statements need not be understood to

       // complete this activity

       if (num1 > num2) { // if num1 is greater than num2,

           maxVal = num1; // then num1 is the maxVal.

       }

       else { // Otherwise,

           maxVal = num2; // num2 is the maxVal.

       }

       return maxVal;

   }

   public static void main(String[] args) {

       double numA = 5.0;

       double numB = 10.0;

       double numY = 3.0;

       double numZ = 7.0;

       double maxSum = 0.0;

       /* Your solution goes here */

       maxSum = findMax(numA, numB); // first call of findMax

       maxSum = maxSum + findMax(numY, numZ); // second call

       System.out.print("maxSum is: " + maxSum);

       return;

   }

}

/*

Output:

maxSum is: 17.0

*/

6 0
2 years ago
When a visitor clicks the submit button on a form, the ______ of each form element is sent?
Bond [772]

In data presentation of computing systems and applications, when a user click the submit button on the form, the name-value pair of each form is sent because it is an open-ended data structure that allows future extension without altering existing code or data.

6 0
2 years ago
Read 2 more answers
Create a single list that contains the following collection of data in the order provided:
ivann1987 [24]

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

8 0
2 years ago
1. Create a view named customer_addresses that shows the shipping and billing addresses for each customer.
Verdich [7]

Answer:

Answer given below

Explanation:

1.

CREATE VIEW CustomerAddresses AS

SELECT custo. CustomerID, EmailAddress , LastName ,FirstName,

bill.Line1 AS BillLine1, bill.Line2 AS BillLine2, bill.City AS BillCity, bill.State AS BillState, bill.ZipCode AS BillZip,

ship.Line1 AS ShipLine1, ship.Line2 AS ShipLine2, ship.City AS ShipCity, ship.State AS ShipState, ship.ZipCode AS ShipZip

FROM Customers custo , Addresses ship , Addresses bill

WHERE custo. BillingAddressID= bill.AddressID AND custo.ShippingAddressID= ship. AddressID;

2.

SELECT CustomerID, LastName, FirstName, BillLine1 FROM CustomerAddresses;

3.

CREATE VIEW OrderItemProducts

AS

SELECT Orders.OrderID, OrderDate, TaxAmount, ShipDate,

ItemPrice, DiscountAmount, (ItemPrice- DiscountAmount) AS FinalPrice,

Quantity, and (Quantity * (ItemPrice-DiscountAmount)) AS ItemTotal,

ProductName FROM

Orders, OrderItems, Products

WHERE

Orders.OrderID = OrderItems.OrderID AND

OrderItems.ProductID = Products. ProductID;

4.

CREATE VIEW ProductSummary

AS

SELECT distinct

ProductName, COUNT(OrderID) AS OrderCount, SUM(ItemTotal) AS OrderTotal

FROM

OrderItemProducts

GROUP BY ProductName;

5.

SELECT ProductName, OrderTotal

FROM ProductSummary P

WHERE 5> (select count(*) FROM ProductSummary S

WHERE P.OrderTotal<S.OrderTotal)

ORDER BY OrderTotal;

5 0
2 years ago
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