Answer: Resolution or DPI, deliverables, and file types are important technical and visual demands to consider when planning a project.
Explanation: Keep in mind whether or not the project will be published in print or on the Web.
Answer:
O(n^2)
Explanation:
The number of elements in the array X is proportional to the algorithm E runs time:
For one element (i=1) -> O(1)
For two elements (i=2) -> O(2)
.
.
.
For n elements (i=n) -> O(n)
If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)
Answer:
I am going to use the Python programming language to answer this. The source code is given below:
print("Enter your tweet here")
user_tweet = input()
decoded_tweet = user_tweet.replace('TTYL', 'talk to you later')
print("This is the decoded tweet: ")
print(decoded_tweet)
Explanation:
In the program the replace() module was used to replace 'TTYL' with 'talk to you later.'
Attached is the screenshot of the output.
Answer:
Option (D) is the correct answer of this question.
Explanation:
Moore's Law relates to Moore's theory that the number of transistors on a microchip doubles every two years while device costs are halved.
Interpretations of Moore's law assert the computing power doubles every 18 months.The Moore's Law theory states that development is exponential.Moore's Law states that every couple of years we should expect our computers to increase their speed and capacity and we'll pay less for them.h
Option(A),Option(B) ,Option(c) and option(E) do not belongs to Moore's law so these options are incorrect options.
<span>BCD only goes from digit 0 (0000) to digit 9 (1001), because for 10 you need two digits, so all you've got to do is make a function that produces high for numbers from 10 (1010) to 15 (1111) as follows:
A3 A2 A1 A0 F
0 0 0 0 0
0 0 0 1 0
0 0 1 0 0
...........................
1 0 0 0 0
1 0 1 0 1
1 0 1 1 1
1 1 0 0 1
1 1 0 1 1
1 1 1 0 1
1 1 1 1 1
Then simplify the function:
F = A3*A2 + A3*A1
Finally just draw or connect the circuit using NAND</span>
