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Ber [7]
2 years ago
5

Match the vocabulary word to the accurate definition. A software program that enables you to search for, interact with, and retr

ieve information resources. A method by which data is transferred from one computer to another through the Internet. Coordinates actions between the user interface and the rendering engine. Handles requests for information resources from networked servers. Includes web pages, images, videos, music files, and other forms of content. Enables a browser to save browsing information. Includes an address bar, Back and Forward buttons, bookmarking menu, and other useful features. Displays content on the screen.
Computers and Technology
2 answers:
AlladinOne [14]2 years ago
5 0

Answer:

web browser

internet protocol

browser engine

networking

information resources

data storage

user interface

rendering engine

Explanation:

gimme a like

SashulF [63]2 years ago
4 0

Answer:

A software program that enables you to search for, interact with, and retrieve information resources: Search Engine

A method by which data is transferred from one computer to another through the Internet Data Transfer

Coordinates actions between the user interface and the rendering engine: Operating Systems

Handles requests for information resources from networked servers: SERVER

Includes web pages, images, videos, music files, and other forms of content WEBSITE

Enables a browser to save browsing information Advanced Settings  

Includes an address bar, Back and Forward buttons, bookmarking menu, and other useful features Web browser

Displays content on the screen. Monitor

Explanation:

If you enable the browser to remember the browser experience, then you certainly need to go inside the advanced settings and from there you can check remember last 7 days and other options. Content is displayed on Monitor, And it is the website that shows images, video, text etc. The information resources are being controlled through the server, and Data transfer is the transfer of the data from one computer to other via a proper network. And the Data is collected, interacted as well as retrieve information via the search engines. And operating system is definitely the interface, and an educated one in between user interface and the rendering engine.

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yes cuz 25x8=200

Explanation:

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_____ remove the part of an image starting from an edge​
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Given six memory partitions of 300 KB, 600 KB, 350 KB, 200 KB, 750 KB, and 125 KB (in order), how would the first-fit, best-fit,
Inga [223]

Answer:

In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.

Explanation:

We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).

Using First-fit

First-fit means you assign the first available memory that can fit a process to it.

  • 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
  • 500KB will fit into the second partition. So, F2 will have a remaining free space of  100KB (600 - 500)
  • 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
  • 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
  • 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)

Using Best-fit

Best-fit means you assign the best memory available that can fit a process to the process.

  • 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
  • 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
  • 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
  • 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
  • 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)

Using Worst-fit

Worst-fit means that you assign the largest available memory space to a process.

  • 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
  • 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
  • 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
  • 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
  • 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
8 0
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Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times
Svet_ta [14]

Answer:

import java.util.Scanner;

public class NumberOfOccurences {

public static void main(String[] args) {

 // Create an object of the Scanner class to allow for user inputs

 Scanner input = new Scanner(System.in);

 // Prompt user to enter text

 System.out.println("Please enter the phrase");

 // Store text in a variable

 String phrase = input.nextLine();

 // Prompt user to enter character to be checked

 System.out.println("Please enter the character to check");

 // Store character in a char variable

 char character = input.next().charAt(0);

 // Create and initialize a variable count to zero

 // count will hold the number of occurrences of the character in the phrase

 int count = 0;

 // Loop through each of the character in the string text

 // At every cycle of the loop, compare the character of the string

 // with the character to be checked.

 // If they match, count is incremented

 for (int i = 0; i < phrase.length(); i++) {

  if (phrase.charAt(i) == character) {

   count++;

  }

 }

 // Print out the number of occurrences due to count

 System.out.println(character + " appears this many times " + count);

}

}

Explanation:

The source code file has been attached to this response and has been saved as "NumberOfOccurrences.java". Please download the file and go through the code including the comment. Pay attention to the comments for readability and understandability.

Hope this helps!

Download java
5 0
2 years ago
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