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Veseljchak [2.6K]
2 years ago
14

A Color class has three public, integer-returning accessor methods: getRed, getGreen, and getBlue, and three protected, void-ret

urning mutator methods: setRed, setGreen, setBlue, each of which accepts an integer parameter and assigns it to the corresponding color component. The class, AlphaChannelColor-- a subclass of Color-- has an integer instance variable, alpha, containing the alpha channel value, representing the degree of transparency of the color. AlphaChannelColor also has a method named dissolve (void-returning, and no parameters), that causes the color to fade a bit. It does this by incrementing (by 1) all three color components (using the above accessor and mutator methods) as well as the alpha component value. Write the dissolve method.
Computers and Technology
1 answer:
jek_recluse [69]2 years ago
6 0

Answer:

The following code are:

public void dissolve() {

setRed(getRed()+1);

setGreen(getGreen()+1);

setBlue(getBlue()+1);

alpha+=1;

}

Explanation:

Here, we define the void type function "dissolve()" inside it, we set three function i.e, "setRed()", "setGreen()", "setBlue()" and then we increment the variable "alpha" by 1.

Inside those three mutators method we set three accessor methods i.e, "getRed()", "getGreen()" , "getBlue()" and increment these accessor by 1.

The values will not be returned by the mutator functions, the accessor will be returned the values.

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The correct answer is A. Familiar words for clues

Explanation:

Finding unfamiliar words is common while reading, especially in texts that belong to a specific field such as medicine, technology, etc. This can be handled through multiple strategies such as using a dictionary, guessing the meaning of the word based on its parts, and using context clues.

In this context, one of the easiest and most time-saving strategy is the use of context clues that implies using the familiar words as clues to guess the meaning of an unfamiliar word. This is effective because in most cases the meaning of an unknown word can be determined using the context of the word or words around the unknown word. Also, this strategy takes little time because you only need to analyze the sentence or paragraph where the unknown word is. Thus, the time-saving strategy to define unfamiliar words involves using familiar words for clues.

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2 years ago
Read 2 more answers
Match the job skills with the correct job role.
Usimov [2.4K]

Answer:

B-1,A-4,C-2,D-3

Explanation:

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2 years ago
Mark and John are developing a program using Python. They name a variable 24_hour_mart, but then recognize that this name violat
77julia77 [94]

Answer:

Option 2: Variable names can not begin with a number.

Explanation:

As given Mark and John named a variable as 24_hour_mart while writing a program in python.

While it is forbidden to name a variable starting with any digit, only alphabets (capital and smaller) and underscore can be the first letter of the variable name.

Moreover, by considering the other options given:

  • Variable name can include the underscore (_) between the words. It is used instead of spaces that are not allowed.
  • There is no upper limit for variable length, it can be of any reasonable length and more than 10 characters say 11 or 12 are reasonable.
  • There is no lower limit for variable length, it can be any reasonable length , even it can be of 1 character.

Variables named in python language must not be the keywords as they are reserved for other purposes.

i hope it will help you!

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A user called to inform you that the laptop she purchased yesterday is malfunctioning and will not connect to her wireless netwo
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Answer:

You can perform the following two steps

Explanation:

  1. Have the user press the appropriate function key combination to enable the wireless radio and then attempt to connect to the wireless network (since by mistake he could have disabled it).
  2. Ask the user to turn on the laptop’s airplane mode and attempt to reconnect to the wireless network (this mode basically what it does is disable adapters and activate it will connect the Wi-Fi network).
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2 years ago
A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info
Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

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