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olchik [2.2K]
2 years ago
11

Lynn runs the locate command and the results include many files from a directory that she doesn't want to include in her search.

Which of the following files could Lynn modify so that the locate command no longer includes those results?a. /etc/locate.d/updatedb.conf
b. /etc/locate.conf
c. /etc/updatedb.conf
d. /etc/locatedb.conf
Computers and Technology
2 answers:
Zinaida [17]2 years ago
5 0

Answer:

C) /etc/updatedb.conf

Explanation:

The locate command actually uses the configuration file located at /etc/updated.conf.

Bumek [7]2 years ago
5 0

Answer:

The correct option is c.  /etc/updatedb.conf

Explanation:

In Linux operating system, locate command is used to search for directories and files in the system.

The locate command uses a database file which is generated by updatedb command to search for a pattern.

Therefore, Lynn can modify the /etc/updatedb.conf file so that the locate command doesn't include those results in the search results.

You can further explore the available options of locate command by typing the man locate command in the terminal.

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#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The fun
adoni [48]

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

       return "not found"

#you can add an elif condition instead of else for not found condition as:

#elif position==-1    

#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

print(string_finder("Georgia Tech", "Idaho"))

Explanation:

The program can also be written in by using string methods.

def string_finder(target,search):  #method definition that takes target string and string to be searched

       if target.startswith(search):  #startswith() method scans the target string and checks if the (substring) search is present at the start of target string

           return "Beginning"  #if above condition it true return Beginning

       elif target.endswith(search):  #endswith() method scans the target string and checks if the (substring) search is present at the end of target string

           return "End" #if above elif condition it true return End

       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

6 0
2 years ago
To gain experience of using and combing different sorting algorithms: election sort, insertion sort, merge sort, and quick sort.
ch4aika [34]

Answer:

Motivation? The search problem.

Sorting algorithms: insertion sort, shellsort, heapsort, mergesort, quicksort, bubblesort

At the very least, "general purpose" sorting algorithms require O(n log n) comparisons

Explanation:

3 0
2 years ago
(Displaying a Sentence with Its Words Reversed) Write an application that inputs a line of text, tokenizes the line with String
Serjik [45]

Answer:

I am writing a JAVA and Python program. Let me know if you want the program in some other programming language.

import java.util.Scanner; // class for taking input from user

public class Reverse{ //class to reverse a sentence

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); //create a Scanner class object

   System.out.print("Enter a sentence: "); //prompts user to enter a sentence

   String sentence = input.nextLine(); // scans and reads input sentence

   String[] tokens = sentence.split(" "); // split the sentence into tokens using split() method and a space as delimiter

   for (int i = tokens.length - 1; i >= 0; i--) { //loop that iterates through the tokens of the sentence in reverse order

       System.out.println(tokens[i]); } } } // print the sentence tokens in reverse order

Explanation:

In JAVA program the user is asked to input a sentence. The sentence is then broken into tokens using split() method. split method returns an array of strings after splitting or breaking the sentence based on the delimiter. Here the delimiter used is space characters. So split() method splits the sentence into tokens based on the space as delimiter to separate the words in the sentence. Next the for loop is used to iterate through the tokens as following:

Suppose the input sentence is "How are you"

After split() method it becomes:

How

are

you

Next the loop has a variable i which initialized to the tokens.length-1. This loop will continue to execute till the value of i remains greater than or equals to 0.

for (int i = tokens.length - 1; i >= 0; i--)

The length of first token i.e you is 3 so the loop executes and prints the word you.

Then at next iteration the value of i is decremented by 1 and now it points at the token are and prints the word are

Next iteration the value of i is again decremented by i and it prints the word How.

This can be achieved in Python as:

def reverse(sentence):

   rev_tokens = ' '.join(reversed(sentence.split(' ')))

   return rev_tokens

   

line = input("enter a sentence: ")

print((reverse(line)))

The method reverse takes a sentence as parameter. Then rev_tokens = ' '.join(reversed(sentence.split(' ')))  statement first splits the sentence into array of words/tokens using space as a delimiter. Next reversed() method returns the reversed sentence.  Next the join() method join the reversed words of the sentence using a space separator ' '.join(). If you want to represent the reversed tokens each in a separate line then change the above statement as follows:

rev_tokens = '\n'.join(reversed(sentence.split(' ')))  

Here the join method joins the reversed words separating them with a new line.

Simply input a line of text and call this reverse() method by passing the input line to it.

4 0
2 years ago
Consider a router that interconnects three subnets: subnet 1, subnet 2, and subnet 3. suppose all of the interfaces in each of t
creativ13 [48]

Answer:

thank God for us you and keep hoping tougher than I thought it would be

4 0
2 years ago
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Poor quality lateral communication will result in which ofthe
zhuklara [117]

Answer:

b

Explanation:

b, lack of coordination

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2 years ago
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