<span>They wrote live updates to a blog, so D. The blog was called "Eye of the Storm." It was written as a series of personal musings and photographs of places where the storm hit- first hand accounts of the disaster. They received a journalism award for it.</span>
Answer:
Option a: a sorted array
Explanation:
Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.
On another hand, any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.
Answer:
Ctrl+Space is the keyboard shortcut to select an entire column.
Explanation:
When you press the Shift+Space shortcut the first time it will select the entire row within the Table. Press Shift+Space a second time and it will select the entire row in the worksheet.
The same works for columns. Ctrl+Space will select the column of data in the Table. Pressing the keyboard shortcut a second time will include the column header of the Table in the selection. Pressing Ctrl+Space a third time will select the entire column in the worksheet.
You can select multiple rows or columns by holding Shift and pressing the Arrow Keys multiple times.
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
