Answer:
personnel strategy
Explanation:
Competitive analysis is a process that involves relating the company to its environment. Competitive analysis helps identify the strengths and weaknesses of the company, as well as the opportunities and threats that affect it within its target market. This analysis is the basis on which the strategy will be designed, for this we must know or intuit as soon as possible:
The nature and success of the probable changes that the competitor may adopt.
The probable response of the competitor to the possible strategic movements that other companies may initiate.
The reaction and adaptation to the possible changes of the environment that may occur from the various competitors.
The competition is made up of companies that operate in the same market and perform the same function within the same group of customers regardless of the technology used for it. It is not, therefore, our competitor that manufactures a generic product like ours, but one that satisfies the same needs as we do with respect to the same target or consumer audience, for example, cinema can be the theme parks competition, since both are embedded in leisure.
Answer:
A
Explanation:
The most likely cause of the problem is that You signed in to BIOS/UEFI with the user power-on password rather than the supervisor power-on password. The User password only enables the machine to boot while the supervisor password allows entering the BIOS settings.
Answer:
You can perform the following two steps
Explanation:
- Have the user press the appropriate function key combination to enable the wireless radio and then attempt to connect to the wireless network (since by mistake he could have disabled it).
- Ask the user to turn on the laptop’s airplane mode and attempt to reconnect to the wireless network (this mode basically what it does is disable adapters and activate it will connect the Wi-Fi network).
Answer:
public static void PrintShampooInstructions(int numberOfCycles){
if (numberOfCycles<1){
System.out.println("Too Few");
}
else if(numberOfCycles>4){
System.out.println("Too many");
}
else
for(int i = 1; i<=numberOfCycles; i++){
System.out.println(i +": Lather and rinse");
}
System.out.println("Done");
}
Explanation:
I have used Java Programming language to solve this
Use if...elseif and else statement to determine and print "Too Few" or "Too Many".
If within range use a for loop to print the number of times
Answer:
C code explained below
Explanation:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int userNum;
bool isPositive;
bool isEven;
scanf("%d", &userNum);
isPositive = (userNum > 0);
isEven = ((userNum % 2) == 0);
if(isPositive && isEven){
printf("Positive even number");
}
else if(isPositive && !isEven){
printf("Positive number");
}
else{
printf("Not a positive number");
}
printf("\n");
return 0;
}
