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astra-53 [7]
2 years ago
8

A BCD code is being transmitted to a remote receiver. The bits are A3, A2, A1, and A0, with A3as the MSB. The receiver circuitry

includes a BCD error detector circuit that examines the received code to see if it is a legal BCD code (i.e., ≤1001). Design this circuit to produce a HIGH for any error condition.
Computers and Technology
1 answer:
NARA [144]2 years ago
3 0
<span>BCD only goes from digit 0 (0000) to digit 9 (1001), because for 10 you need two digits, so all you've got to do is make a function that produces high for numbers from 10 (1010) to 15 (1111) as follows:
A3 A2 A1 A0   F
 0    0    0    0    0
 0    0    0    1    0
 0    0    1    0    0
 ...........................
 1    0    0    0    0
 1    0    1    0    1
 1    0    1    1    1
 1    1    0    0    1
 1    1    0    1    1
 1    1    1    0    1
 1    1    1    1    1
 
Then simplify the function: F = A3*A2 + A3*A1 Finally just draw or connect the circuit using NAND</span>
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