Static void PrintTriangle(int n){ for(;n>0;n--) { Console.WriteLine(new String('*', n)); }}
Answer:
b) Bounded Waiting
Explanation:
int currentThread = 1;
bool thread1Access = true;
bool thread2Access = true;
thread1 { thread2 {
While (true) {
While (true)
{
while(thread2Access == true)
{
while(thread1Access == true)
{
If (currentThread == 2) {
If (currentThread == 1)
{
thread1Access = false; thread2Access = false;
While (currentThread == 2);
While (currentThread == 1);
thread1Access = true; thread2Access = true;
} }
/* start of critical section */ /* start of critical section */
currentThread = 2 currentThread = 1
… ...
/* end of critical section */ /* end of critical section */
thread1Access = false; thread2Access = false;
… ...
} }
} }
} }
It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.
Answer:
Correct code for the above question which is written after the defined list to display the output.
for x,y in country_pop.items(): #for loop to prints the list items.
print(str(x)+" has "+str(y)+" people") #print function to print the value.
Output:
- The above code is in python language which display the output as the above question demands.
Explanation:
- The above question code is written in python language to display the result, but this code is not correct.
- The above code needs a 'for' loop, which will render the list item one by one.
- The above-list defined in the form of key-value pair, So there is a need for the ''item" function which is the part of the python dictionary to display the list items.
- There also needs to define the two variables in the for loop, one is for key and the other is for value.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
The keyboard is used to input information. (Entering data)
