All categories

2 years ago

Complete the function to replace any period by an exclamation point. Ex: "Hello. I'm Miley. Nice to meet you." becomes:

Computers and Technology

1 answer:

vodomira [7]2 years ago

6 0

Answer:

Here is the complete function:

void MakeSentenceExcited(char* sentenceText) { // function that takes the text as parameter and replaces any period by an exclamation point in that text

int size = strlen(sentenceText); //returns the length of sentenceText string and assigns it to size variable

char * ptr; // character type pointer ptr

ptr = sentenceText; // ptr points to the sentenceText string

for (int i=0; i<size; i++){ //iterates through the sentenceText string using i as an index

if (sentenceText[i]=='.'){ // if the character at i-th index of sentenceText is a period

sentenceText[i]='!'; } } } //places exclamation mark when it finds a period at i-th index of sentenceText

Explanation:

The program works as follows:

Suppose we have the string:

sentenceText = "Hello. I'm Miley. Nice to meet you."

The MakeSentenceExcited method takes this sentenceText as parameter

int size = strlen(sentenceText) this returns the length of sentenceText

The size of sentenceText is 35 as this string contains 35 characters

size = 35

Then a pointer ptr is declared which is set to point to sentenceText

for (int i=0; i<size; i++) loop works as follows:

1st iteration:

i=0

i<size is true because i=0 and size = 35 so 0<35

So the body of loop executes:

if (sentenceText[i]=='.') statement checks :

if (sentenceText[0]=='.')

The first element of sentenceText is H

H is not a period sign so the statement inside if statement does not execute and value of i increments to 1. Now i = 1

2nd iteration:

i=1

i<size is true because i=1 and size = 35 so 1<35

So the body of loop executes:

if (sentenceText[i]=='.') statement checks :

if (sentenceText[1]=='.')

This is the second element of sentenceText i.e. e

e is not a period sign so the statement inside if statement does not execute and value of i increments to 1. Now i = 2

So at each iteration the if condition checks if the character at i-th index of string sentenceText is a period.

Now lets see a case where the element at i-th index is a period:

6th iteration:

i=5

i<size is true because i=5 and size = 35 so 5<35

So the body of loop executes:

if (sentenceText[i]=='.') statement checks :

if (sentenceText[5]=='.')

This is the character at 5th index of sentenceText i.e. "."

So the if condition evaluates to true and the statement inside if part executes:

sentenceText[i]='!'; statement becomes:

sentenceText[5]='!'; this means that the character at 5th position of sentenceText string is assigned an exclamation mark.

So from above 6 iterations the result is:

Hello!

This loop continues to execute until all the characters of sentenceText are checked and when the value of i gets greater than or equal to the length of sentenceText then the loop breaks.

The screenshot of the program along with its output is attached.

You might be interested in

c++ You are given an array A representing heights of students. All the students are asked to stand in rows. The students arrive

Lilit [14]

The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.

#include<stdio.h>

#include<string.h>

int* uniqueValue(int input1,int input2[])

{

int left, current;

static int arr[4] = {0};

int i = 0;

for(i=0;i<input1;i++)

{

current = input2[i];

left = 0;

if(current > 0)

left = arr[(current-1)];

if(left == 0 && arr[current] == 0)

{

arr[current] = input1-current;

}

else

{

for(int j=(i+1);j<input1;j++)

{

if(arr[j] == 0)

{

left = arr[(j-1)];

arr[j] = left - 1;

}

return arr;

}

4 0

2 years ago

Robin wants her presentation to move from one slide to another with special motion effects. Which option should Robin use?

topjm [15]

If this is in power point, then she should use the <em>transitions </em>tab on the ribbon. =)

3 0

2 years ago

Read 2 more answers

Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco

harina [27]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {

//executes when condition1 evaluates to true

if(condition2) {

//executes when condition1 and condition2 evaluate to true

} else if(condition3) {

//when condition1 is true and condition3 is true

} else {

//condition1 is true but neither condition2 nor conditions3 are true

} }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of one of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){ //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1 is true but neither condtion2 nor condtion3 are true }

This can further be modified to one conditional as:

if(!condition3){

// when condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40){

if (busArrived=="yes") {

if (!sick) {

if (homework=="done") {

printf("Go to school.");

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{ cout<<"Go to school."; }

6 0

2 years ago

What output is produced by the following program segment? Why? (Recall that name.charAt(i) is the i-th character in the string,

vekshin1

Answer:

The output is:

Explanation:

The code snippet print the beginning letter of each word in the given name.

In the for loop snippet:

first the program check if startWord is true and it is true, then it print the value of the character at index 0. Then it check if value of character is empty. If it is empty, startWord is initialized to true else it is initialized to false.

The loop only print a character when the value of i are 0, 8 and 11 which are also the beginning character of a word.

8 0

2 years ago

In a single file, you wrote a bike class and used this line of code in the program.

Elza [17]

Answer:

Explanation:

Based on the available options the one that would be correct would be that the code to define your class (beginning with "class bike") must come before the line "bikeA = bike('Acme' 111)." This is because the line of code declaring the object and initializing it needs to be able to grab the information of the class that it is creating an object of. To do this, the class would need to have already been compiled by the program. It is good practice to have each class definitions as its own separate files but this is not a necessity.

5 0

2 years ago