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polet [3.4K]
2 years ago
7

Consider the packets exchanged in TCP connection setup between Host A and Host B. Assume that Host A's initial sequence number i

s 2345 and Host B's initial sequence number is 7777. Fill in the sequence numbers and ack numbers that correctly construct the sequence
Computers and Technology
1 answer:
Rasek [7]2 years ago
6 0

Answer:

I think that part C correct option

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For his class project, Matt has to create an image in a color scheme that has shade or tint variations of the same hue. Which co
Alex

Answer:

B.Monochromatic

Explanation:

mono means one

5 0
2 years ago
9. Which of the following are true for all regular languages and all homomorphisms? (a) h (L1 ∪ L2)= h (L1) ∩ h (L2). (b) h (L1
mixer [17]

Answer:

h (L1 ∪ L2)= h (L1) ∩ h (L2).

This is true.

There will be w ∈  (L1 ∪ L2) for any s ∈ h (L1 ∪ L2) in such a way that s=h(w)

we can assume that w ∈ L1

So In this case h(w) ∈ L (S1). Hence s ∈ L(S1)

for any s ∈ h (L1) U h(L2)

We can assume that s ∈ L(S1)

There exists w ∈ L1 such that s= h(w)

In this case it is w ∈ L1 U L2 as well.

Hence , s ∈ h (L1 U L2)

Explanation

consider  = 0,1 and  = a,b and h(0) = a , h(1) = ab

(a) Consider L1 = 10,01 and L2 = 00,11

   Now L1 ∪ L2 = 00,01,10,11

   h (L1 ∪ L2) = h(00) , h(01) , h(10) , h(11) = h(0)h(0) , h(0)h(1) , h(1)h(0) , h(1)h(1)

  = aa, aab , aba , abab

Hence h (L1 ∪ L2) = aa, aab , aba , abab .

Here h (L1) = h(10) , h(01) = h(1)h(0) , h(0)h(1) = aba , aab

Hence h (L1) = aba , aab .

Here h (L2) = h(00) , h(11) = h(0)h(0), h(1)h(1) = aa, abab

Hence h(L2) = aa, abab.

Finally Hence , h (L1 ∪ L2)= h (L1) ∩ h (L2).

5 0
2 years ago
Write a C# program named ProjectedRaises that includes a named constant representing next year’s anticipated 4 percent raise for
nydimaria [60]

Answer:

using System;

class ProjectedRaises {

 static void Main() {

     const float raise = 0.04f;

     double salary1 = 0.0f,salary2 = 0.0f,salary3 = 0.0f;

Console.WriteLine("Current salary for each employee: ");

     salary1 = Single.Parse(Console.ReadLine());

     salary2 = Single.Parse(Console.ReadLine());

     salary3 = Single.Parse(Console.ReadLine());

     salary1 = salary1 + raise * salary1;

     salary2 = salary2 + raise * salary2;

     salary3 = salary3 + raise * salary3;

     Console.WriteLine("Next year salary for the employees are: ");

     Console.WriteLine(Math.Round(salary1));

     Console.WriteLine(Math.Round(salary2));

     Console.WriteLine(Math.Round(salary3));

}

}

Explanation:

This declares and initializes variable raise as a float constant

     const float raise = 0.04f;

This declares the salary of each employee as double

     double salary1 = 0.0f,salary2 = 0.0f,salary3 = 0.0f;

This prompts the user for the salaries of the employee

Console.WriteLine("Current salary for each employee: ");

The next three lines get the salary of the employees

<em>      salary1 = Single.Parse(Console.ReadLine());</em>

<em>      salary2 = Single.Parse(Console.ReadLine()); </em>

<em>      salary3 = Single.Parse(Console.ReadLine()); </em>

The next three lines calculate the new salaries of the employees

<em>      salary1 = salary1 + raise * salary1;</em>

<em>      salary2 = salary2 + raise * salary2;</em>

<em>      salary3 = salary3 + raise * salary3;</em>

This prints the header

     Console.WriteLine("Next year salary for the employees are: ");

The next three lines print the new salaries of the employees

     Console.WriteLine(Math.Round(salary1));

     Console.WriteLine(Math.Round(salary2));

     Console.WriteLine(Math.Round(salary3));

7 0
2 years ago
Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times
otez555 [7]

Answer:

The program written in python is as follows

def countchr(phrase, char):

     count = 0

     for i in range(len(phrase)):

           if phrase[i] == char:

                 count = count + 1

     return count

phrase = input("Enter a Phrase: ")

char = input("Enter a character: ")

print("Occurence: ",countchr(phrase,char))

Explanation:

To answer this question, I made use of function

This line defines function countchr

def countchr(phrase, char):

This line initializes count to 0

     count = 0

This line iterates through each character of input phrase

     for i in range(len(phrase)):

This line checks if current character equals input character

           if phrase[i] == char:

The count variable is incremented, if the above condition is true

                 count = count + 1

The total number of occurrence is returned using this line

     return count

The main method starts here; This line prompts user for phrase

phrase = input("Enter a Phrase: ")

This line prompts user for a character

char = input("Enter a character: ")

This line prints the number of occurrence of the input charcater in the input phrase

print("Occurence: ",countchr(phrase,char))

4 0
2 years ago
Using range(1,101), make two list, one containing all even numbers and other containing all odd numbers. How can I do this on Py
jeka94

Answer:

even = []

odd = []

for i in range(1,101):

if i % 2 == 0:

even.append(i)

else:

odd.append(i)

4 0
1 year ago
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