Answer:
- def is_prime(n):
- for i in range(2, n):
- if(n % i == 0):
- return False
- return True
-
- prime_truths = [is_prime(x) for x in range(2,101)]
- print(prime_truths)
Explanation:
The solution code is written in Python 3.
Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.
Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.
After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).
Answer:
I will write the code in C++ and JAVA
Explanation:
<h2>
JAVA CODE</h2>
public class Main
{ public static void main(String[] args) {
// displays Gershwin,George
System.out.println("Gershwin,George"); } }
<h2>
C++ Code:</h2>
#include <iostream>
using namespace std;
int main()
{ cout<<"Gershwin,George";
}
// displays last name Gershwin followed by , followed by first name George
//displays Gershwin,George as output.
Answer:
cubeVolume = IMath.toThePowerOf(cubeSide, 3);
Explanation:
Following is the explanation for above statement:
Left side:
cubeVolume is a variable with data-type int, it will store the integer value that is the output from right side.
Right side:
- IMath is the class name.
- toThePowerOf is the built-in function that takes two arguments of data type int. First is the base and second is the power(exponent) separated by comma. In place of first argument that is the base variable we will pass the variable cubeSide that has been declared and initialize.
- Now the output will be stored in the variable cubeVolume.
i hope it will help you!
Ok we will do it for you cause they are very mean
