How would GIS, GPS, or remote sensing technology be used to evaluate the destruction caused by a tornado in Oklahoma?

The alternative to encapsulating security protocol (esp) is _________.

Lina20 [59]

The alternative to Encapsulating Security Protocol (ESP) is Authentication Header (AH). Hope this helped!

8 0

2 years ago

Darius needs to include contact information in an email that he is sending to a colleague . Which option should he choose from t

melamori03 [73]

The question is incomplete:

Darius needs to include contact information in an email that he is sending to a colleague . Which option should he choose from the ribbon?

-Attach File

-Attach Item

-Attach Policy

-Attach Signature

Answer:

-Attach Signature

Explanation:

-Attach file is an option that allows you to include any type of file that you need to send in the email.

-Attach Item is an option that allows you to include an element from your email like a message in your inbox to the current one you are writing.

-Attach Policy is not an option.

-Attach Signature is an option that allows you to include a previously created signature with the contact information at the end of the message.

According to this, the answer is that the option that Darius should choose from the ribbon is attach signature because he needs to include contact information.

4 0

2 years ago

Define a new object in variable sculptor that has properties "name" storing "Michelangelo"; "artworks" storing "David", "Moses"

Talja [164]

Answer:

String [] artworks = {"David","Moses","Bacchus"};

Sculptor sculptor = new Sculptor("Michaelangelo",artworks,

"March 6, 1475","February 18, 1564");

Explanation:

To solve this problem effectively;
Create a class (Java is used in this case) with fields for name, artworks(an array of string), bornDate and diedDate.
Create a constructor to initialize this fields
In a seperate class SculptorTest, within the main method create an array of String artworks and initialize to {"David","Moses","Bacchus"};
Create a new object of the class with the line of code given in the answer section.
See code for complete class definition below:

public class Sculptor {

private String name;

private String [] artworks;

private String bornDate;

private String diedDate;

public Sculptor(String name, String[] artworks, String bornDate, String diedDate) {

this.name = name;

this.artworks = artworks;

this.bornDate = bornDate;

this.diedDate = diedDate;

}

}

//Test Class with a main method

class SculptorTest{

public static void main(String[] args) {

String [] artworks = {"David","Moses","Bacchus"};

Sculptor sculptor = new Sculptor("Michaelangelo",artworks,

"March 6, 1475","February 18, 1564");

}

}

6 0

2 years ago

To keep from overwriting existing fields with your Lookup you can use the ____________ clause.

Radda [10]

I believe the answer is outputnew
The main difference between the output new and the output is that outputnew won't overrite the alredy existing description field.
If you don't put this clause, Splunk would adds all the field names and values to your events by through the lookup.

3 0

2 years ago

Read 2 more answers

Write a function addOddMinusEven that takes two integers indicating the starting point and the end point. Then calculate the sum

snow_lady [41]

Answer:g

public static int addOddMinusEven(int start, int end){

int odd =0;

int even = 0;

for(int i =start; i<end; i++){

if(i%2==0){

even = even+i;

}

else{

odd = odd+i;

}

return odd-even;

}

Explanation:

Using Java programming language:

The method addOddMinusEven() is created to accept two parameters of ints start and end
Using a for loop statement we iterate from start to end but not including end
Using a modulos operator we check for even and odds
The method then returns odd-even
See below a complete method with a call to the method addOddMinusEven()

public class num13 {

public static void main(String[] args) {

int start = 2;

int stop = 10;

System.out.println(addOddMinusEven(start,stop));

}

public static int addOddMinusEven(int start, int end){

int odd =0;

int even = 0;

for(int i =start; i<end; i++){

if(i%2==0){

even = even+i;

}

else{

odd = odd+i;

}

return odd-even;

}

8 0

2 years ago