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2 years ago

An online game is played with two dice. In this context, explain what is meant by decomposition in a simple way.

1 answer:

8 0

Their value is random, so you need to generate two numbers between 1 & 6.
You may need to display the numbers
The main part of the program needs to know the numbers to limit what the user may do next.

That's most of the first level of decomposition. You need to keep decomposing (breaking into smaller simpler pieces) (think of an outline) and deciding what objects, functions, data structures and logic you're going to code this.

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With Voice over Internet Protocol (VoIP), _____. a. voicemails cannot be received on the computer b. call quality is significant

Pachacha [2.7K]

Answer:

c. Users can have calls forwarded from anywhere in the world

Explanation:

As all you need is the internet, there would be no need to try to sort out roaming as you would on a regular phone line

4 0

1 year ago

B.) Define latency and jitter for service flow in a fixed wireless system.

yuradex [85]

The answer would be between the base station and the subscriber station.

7 0

2 years ago

A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, an

yulyashka [42]

The question is incomplete. It can be found in search engines. However, kindly find the complete question below:

Question

Cites as a pitfall the utilization of a subset of the performance equation as a performance metric. To illustrate this, consider the following two processors. P1 has a clock rate of 4 GHz, average CPI of 0.9, and requires the execution of 5.0E9 instructions. P2 has a clock rate of 3 GHz, an average CPI of 0.75, and requires the execution of 1.0E9 instructions. 1. One usual fallacy is to consider the computer with the largest clock rate as having the largest performance. Check if this is true for P1 and P2. 2. Another fallacy is to consider that the processor executing the largest number of instructions will need a larger CPU time. Considering that processor P1 is executing a sequence of 1.0E9 instructions and that the CPI of processors P1 and P2 do not change, determine the number of instructions that P2 can execute in the same time that P1 needs to execute 1.0E9 instructions. 3. A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, and consider that the processor with the largest MIPS has the largest performance. Check if this is true for P1 and P2. 4. Another common performance figure is MFLOPS (millions of floating-point operations per second), defined as MFLOPS = No. FP operations / (execution time x 1E6) but this figure has the same problems as MIPS. Assume that 40% of the instructions executed on both P1 and P2 are floating-point instructions. Find the MFLOPS figures for the programs.

Answer:

(1) We will use the formula:

CPU time = number of instructions x CPI / Clock rate

So, using the 1 Ghz = 10⁹ Hz, we get that

CPU time₁ = 5 x 10⁹ x 0.9 / 4 Gh

= 4.5 x 10⁹ / 4 x 10⁹Hz = 1.125 s

and,

CPU time₂ = 1 x 10⁹ x 0.75 / 3 Ghz

= 0.75 x 10⁹ / 3 x 10⁹ Hz = 0.25 s

So, P2 is actually a lot faster than P1 since CPU₂ is less than CPU₁

(2)

Find the CPU time of P1 using (*)

CPU time₁ = 10⁹ x 0.9 / 4 Ghz

= 0.9 x 10⁹ / 4 x 10⁹ Hz = 0.225 s

So, we need to find the number of instructions₂ such that CPU time₂ = 0.225 s. This means that using (*) along with clock rate₂ = 3 Ghz and CPI₂ = 0.75

Therefore, numbers of instruction₂ x 0.75 / 3 Ghz = 0.225 s

Hence, numbers of instructions₂ = 0.225 x 3 x 10⁹ / 0.75 = 9 x 10⁸

So, P1 can process more instructions than P2 in the same period of time.

(3)

We recall that:

MIPS = Clock rate / CPI X 10⁶

So, MIPS₁ = 4GHZ / 0.9 X 10⁶ = 4 X 10⁹HZ / 0.9 X 10⁶ = 4444

MIPS₂ = 3GHZ / 0.75 X 10⁶ = 3 x 10⁹ / 0.75 X 10⁶ = 4000

So, P1 has the bigger MIPS

(4)

We now recall that:

MFLOPS = FLOPS Instructions / time x 10⁶

= 0.4 x instructions / time x 10⁶ = 0.4 MIPS

Therefore,

MFLOPS₁ = 1777.6

MFLOPS₂ = 1600

Again, P1 has the bigger MFLOPS

3 0

1 year ago

A time-saving strategy that helps define unfamiliar words involves using

yuradex [85]

The correct answer is A. Familiar words for clues

Explanation:

Finding unfamiliar words is common while reading, especially in texts that belong to a specific field such as medicine, technology, etc. This can be handled through multiple strategies such as using a dictionary, guessing the meaning of the word based on its parts, and using context clues.

In this context, one of the easiest and most time-saving strategy is the use of context clues that implies using the familiar words as clues to guess the meaning of an unfamiliar word. This is effective because in most cases the meaning of an unknown word can be determined using the context of the word or words around the unknown word. Also, this strategy takes little time because you only need to analyze the sentence or paragraph where the unknown word is. Thus, the time-saving strategy to define unfamiliar words involves using familiar words for clues.

6 0

1 year ago

Read 2 more answers

Write a program to input value of three sides, to check triangle is triangle is possible to form of not

NeTakaya

Answer:

Explanation:

import java.util.Scanner;

public class KboatTriangleAngle

{

public static void main(String args[]) {

Scanner in = new Scanner(System.in);

System.out.print("Enter first angle: ");

int a1 = in.nextInt();

System.out.print("Enter second angle: ");

int a2 = in.nextInt();

System.out.print("Enter third angle: ");

int a3 = in.nextInt();

int angleSum = a1 + a2 + a3;

if (angleSum == 180 && a1 > 0 && a2 > 0 && a3 > 0) {

if (a1 < 90 && a2 < 90 && a3 < 90) {

System.out.println("Acute-angled Triangle");

}

else if (a1 == 90 || a2 == 90 || a3 == 90) {

System.out.println("Right-angled Triangle");

}

else {

System.out.println("Obtuse-angled Triangle");

}

else {

System.out.println("Triangle not possible");

}

OUTPUT:

3 0

2 years ago