Ok we will do it for you cause they are very mean
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
Answer:
Explanation:
The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.
public static T minmax(ArrayList<T> mylist) {
T min = new T();
T max = new T();
for (int x = 0; x < mylist.size(); x++) {
if (mylist.get(x) > max) {
max = mylist.get(x);
} else if (mylist.get(x) < min) {
min = mylist.get(x);
}
}
return (min, max);
}
Explanation:
Execution step:
1. Starting the program
2. It will get the animal name
3. Check whether the animal eats only plants. Then it prints "Herbivore". If the condition is false, it prints "carnivore".
4. Stop the program
To identify input, output and decision:
Start and Stop (oval): These are neither input nor output
Does it eat only plants?: Decision making statement ("d")
Read the names of the animals(Parallelogram): Input ("i")
Print Herbivore, Print Carnivore: Output "o"
Scenario 1: Input is lion
1. Start
2. Reads the input as "lion"
3. Check if lion eats only plants. So here it is false
4. Print "Carnivore"
5. Stop
Scenario 1: Input is Elephant
1. Start
2. Reads the input as "Elephant"
3. Check if lion eats only plants. So here it is true
4. Print "Herbivore"
5. Stop
