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CaHeK987 [17]
2 years ago
12

In the description of the Hack machine language in chapter 4, it is stated that in well-written programs a C-instruction that ma

y cause a jump should not contain a reference to M, and vice versa. Discuss why this should be avoided.
The last instruction (0; JMP) effects an unconditional jump. Since the C-instruction syntax requires that we always effect some computation, we instruct the ALU to compute 0 (an arbitrary choice), which is ignored.
The programmer can use the A register to select either a data memory location for a subsequent C-instruction involving M, or an instruction memory location for a subsequent C-instruction involving a jump. Thus, to prevent conflicting use of the A register, in well-written programs a C-instruction that may cause a jump (i.e., with some non-zero j bits) should not contain a reference to M, and vice versa.

Computers and Technology
1 answer:
kati45 [8]2 years ago
4 0

Answer:

To avoid conflicting uses of A register, few well-written programs follow the best practice, i.e, avoiding reference to M and vice versa. The programmer can use the A register to select either a data memory location for a subsequent C-instruction involving M, or an instruction memory location for a subsequent C-instruction involving a jump. Thus, to prevent the conflicting use of the A register, in well-written programs a C-instruction that may cause a jump (i.e., with some non-zero j bits) should not contain a reference to M, and vice versa.

Image is attached for better demonstration and understanding.

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The program to calculate the total paint cost and other values is given below.

#include <iostream>

using namespace std;

int main() {  

 int rooms, laborChrg = 18;

 float paintChrg;

 float feetPerRoom[rooms];  

 float paintReq, laborHrs, paintCost, laborCost, totalCost, totalsqft=0;  

 cout<<"Enter the number of rooms to be painted "<<endl;

 cin>>rooms;  

 for(int i=0; i <= rooms; i++)

 {

 cout<<"Enter the square feet in room "<<endl;

 cin>>feetPerRoom[i];  

 // shortcut operator which is equivalent to totalsqft = totalsqft +     feetPerRoom[i];

 totalsqft += feetPerRoom[i];

 }  

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 cin>>paintChrg;  

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 cout<<"The number of gallons of paint required "<<paintReq<<endl;

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 cout<<"The cost of the paint is "<<paintCost<<endl;

 cout<<"The labor charges are "<<laborHrs<<endl;

 cout<<"The Total cost of the paint job is "<<totalCost<<endl;  

 return 0;

}

Explanation:

The header files for input and output are imported.

#include <iostream>

using namespace std;

All the variables are taken as float except labour charge per hour and number of rooms.

The user is asked to input the number of rooms to be painted. An array holds the square feet in each room to be painted.

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;  

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];  

totalsqft += feetPerRoom[i];

}  

The above code asks for square feet in each room and calculates the total square feet to be painted simultaneously.

All the data to be displayed is calculated based on the values of labor charge per hour and gallons of paint needed, given in the question.

laborHrs = (totalsqft/115)*8;

laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

All the calculated values are displayed in the mentioned order.

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