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1 year ago

Which of the following is not true of how computers represent complex information

Computers and Technology

2 answers:

mote1985 [20]1 year ago

5 0

Answer: c. Depending on context the same sequence of bits may represent different types of information.

Explanation:

The options for the question are:

A. Computing devices use patterns of bits to represent complex information

B. Abstraction helps represent complex information by surfacing complexity that might otherwise be hidden

C. Depending on context the same sequence of bits may represent different types of information

D. Common abstractions that are represented by computing devices include numbers, characters, and color.

The following are true of how computers represent complex information:

• Computing devices use patterns of bits to represent complex information

• helps represent complex information by surfacing complexity that might otherwise be hidden

• Common abstractions that are represented by computing devices include numbers, characters, and color.

Therefore, the option that is not true of how computers represent complex information is that "depending on context the same sequence of bits may represent different types of information".

Triss [41]1 year ago

5 0

Answer: B

Explanation:

Because this one is correct and c is wrong.

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Digital cellphones use Digital Compression to reduce the size of the channels that are required, by scattering the digital fragments of conversations over many channels

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2 years ago

In the Budget Details sheet, if you wish to autofill with the formula, you must use a ______ reference for the LY Spend Total ce

ahrayia [7]

Answer:

The answer is A.Absolute reference.

Explanation:

Absolute reference is a cell reference whose location remains constant when the formula is copied.

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2 years ago

Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where

kozerog [31]

Answer:

public class FindDuplicate{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int n = 5;
int arr[] = new int[n];
for(int i=0; i < arr.length; i++){
int inputNum = input.nextInt();
if(inputNum >=1 && inputNum <=n) {
arr[i] = inputNum;
}
}
for(int j =0; j < arr.length; j++){
for(int k = 0; k < arr.length; k++){
if(j == k){
continue;
}else{
if(arr[j] == arr[k]){
System.out.println("True");
return;
}
}
}
}
System.out.println("False");
}
}

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

7 0

1 year ago

Create a single list that contains the following collection of data in the order provided:

ivann1987 [24]

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

8 0

2 years ago

GJAUDRO: A member of a team. Question 2 with 1 blankARBCUE: Activity that is practiced under the water. Question 3 with 1 blankE

kramer

Answer:

1 jugador

2 bucear

3 equipo

4 ciclismo

5 pasear

6 tenis

Explanation:

ur welcome

6 0

2 years ago