All categories

2 years ago

4.2 Code Practice: Question 2

Computers and Technology

2 answers:

Iteru [2.4K]2 years ago

6 0

Answer:

pet = input(str("What pet do you have?"))

totalPets = 1

while(pet!="rock"):

print("You have a " + str(pet) + " with a total of " + str(int(totalPets)) + " pet(s)")

totalPets = totalPets+ 1

pet = input(str("What pet do you have?"))

(Let me know if you find any errors, my python is rusty.)

skad [1K]2 years ago

5 0

I've included my code in the picture below. Best of luck.

You might be interested in

Which set of variables will make code easier to understand?

Alecsey [184]

Answer:

sum, price, count

Explanation:

Programmers should use significant names for the variables.

Not only it makes it easier for them to remember what kind of information is stored in each variable, but it also makes life simpler for anyone who would read the code later.

Names like sum, price and count are significant names ( assuming they actually hold this kind of data), and will make the re-reading of the program code much easier.

8 0

2 years ago

____ twisted pair is the least quality twisted pair wire that should be used in a data/voice application.

xxMikexx [17]

Answer:

Category 5 (Cat 5) twisted pair is the least quality twisted pair wire that should be used.

Explanation:

The reason is as follows:

Category 1 twisted pair is not suitable for transmitting data but comes in handy for telephone communications. Hence, it should not be used in a data/voice application.
Category 2 twisted pair is suitable for data transmission, however, it can only transmit at 4Mbps which is very slow. Hence, it should not be used in a data/voice application.
Category 3 twisted pair can transmit data with speed reaching 10Mbps which is slow for voice/data communication.
Category 4 twisted pair can transmit data with speed reaching 16Mbps and is used in token ring networks. It is slow for communicating in a voice/data application.
Category 5 twisted pair is the least qualified to be used in a voice/data application because it can transmit data at speeds that reach 100Mbps.

Hence, Cat 5 or Category 5 twisted pair is the least quality twisted pair that should be used in a data/voice application.

6 0

2 years ago

Ethan is a systems developer. He is working on a system where he will implement independent solutions for different processes. W

Igoryamba

The correct answer for this question is this one: " c.huge initial investment"
Ethan is a systems developer. He is working on a system where he will implement independent solutions for different processes. The possible drawback of using such a system is that huge initial investment

Hope this helps answer your question and have a nice day ahead.

8 0

2 years ago

Consider a short, 10-meter link, over which a sender can transmit at a rate of 150 bits/sec in both directions. Suppose that pac

Katarina [22]

Answer:

The Tp value 0.03 micro seconds as calculated in the explanation below is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP.

Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

Explanation:

Given details are below:

Length of the link = 10 meters

Bandwidth = 150 bits/sec

Size of a data packet = 100,000 bits

Size of a control packet = 200 bits

Size of the downloaded object = 100Kbits

No. of referenced objects = 10

Ler Tp to be the propagation delay between the client and the server, dp be the propagation delay and dt be the transmission delay.

The formula below is used to calculate the total time delay for sending and receiving packets :

d = dp (propagation delay) + dt (transmission delay)

For Parallel downloads through parallel instances of non-persistent HTTP :

Bandwidth = 150 bits/sec

No. of referenced objects = 10

For each parallel download, the bandwith = 150/10

= 15 bits/sec

10 independent connections are established, during parallel downloads, and the objects are downloaded simultaneously on these networks. First, a request for the object was sent by a client . Then, the request was processed by the server and once the connection is set, the server sends the object in response.

Therefore, for parallel downloads, the total time required is calculated as:

(200/150 + Tp + 200/150 + Tp + 200/150 + Tp + 100,000/150 + Tp) + (200/15 + Tp + 200/15 + Tp + 200/150 + Tp + 100,000/15 + Tp)

= ((200+200+200+100,00)/150 + 4Tp) + ((200+200+200+100,00)/15 + 4Tp)

= ((100,600)/150 + 4Tp) + ((100,600)/15 + 4Tp)

= (670 + 4Tp) + (6706 + 4Tp)

= 7377 + 8 Tp seconds

Thus, parallel instances of non-persistent HTTP makes sense in this case.

Let the speed of propogation of the medium be 300*106 m/sec.

Then, Tp = 10/(300*106)

= 0.03 micro seconds

The Tp value 0.03 micro seconds as calculated above is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP. Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

4 0

2 years ago

___refers to self-acting or self-operating.

lisabon 2012 [21]

Answer:

do it to me watch this

Explanation:

trailing zeros in a whole number with no decimal shown are NOT significan

6 0

2 years ago