Answer:
=IF( B7 = 12, ( IF( B10 = 10,"YES", "")), 7) and PRESS ENTER
Explanation:
the above logical if function checks the following
-IF cell B7 is 12, if true, check the value of cell B10, IF cell B10 contains 10 the function should produce YES as output to whatever cell selected, IF B10 is not 10 output of the function should be an empty string, IF B7 is not equal to 12 the the output of the function should be 7.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
