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sweet-ann [11.9K]
2 years ago
12

Given an integer variable strawsOnCamel, write a statement that uses the auto-increment operator to increase the value of that v

ariable by 1.
Computers and Technology
1 answer:
Reptile [31]2 years ago
5 0

Answer:

The program to this question can be given as follows:

Program:

#include <stdio.h> //include header file for using basic function

int main() //defining main method

{

int strawsOnCamel=0; //defining integer variable and assign value

for(int i=1;i<=5;i++) //loop for increment integer variable value

{

//code

strawsOnCamel++; //increment value by 1

printf("%d\n", strawsOnCamel); //print value

}

return 0;

}

Output:

1

2

3

4

5

Explanation:

In the C language code above the header file is entered, and a whole variable strawsOnCamel is specified within the main method, which gives a value of 0.

  • Then a for loop is defined inside a loop an integer variable i declared that starts from 1 and ends with 5.
  • Inside a loop, the strawsOnCamel variable is used that increments its value by 1 and prints its value.

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E xercise 17.2.4: The following is a sequence of undo-log records written by two transactions T and U: &lt; START T&gt;; ; &lt;
masya89 [10]

Answer:

Check the explanation

Explanation:

The following is a sequence of Undo — log records written by two transactions.

<START 1>; <F, A, 10>; <START U>; <U, B, 20>; <F, C, 30>; <U, D, 40>; <COMMIT U>; <T, E, 50>; <COMMIT T>; (a) < START U >;

If the system crashes after the log < START U >,

Then we have log records will be shown below.

<START U>;

<T, A, 10>;

<START T>;

SYSTEM CRASHED

The recovery manager sees the Undo - Redo log and inspect the both trans-actions T and U are not committed. Then those elements changed by both transactions are arranged to their old values.

  1. Transaction T changes the element A.
  2. Then the Element A is arranged to old value A=10.
  3. Transaction U did not change any existing element in the records.
  4. So, not anything to do with transaction U.

(B) < T, E, 50>;

If the system crashes after the log < T, E, 50>;

Then we have log records will be shown below .

START T>;

<T, A, 10>;

<START U>;

<U, B, 20>;

<T, C, 30>;

<U, D, 40>;

<COMMIT U>;

<T, E, 50>;

SYSTEM CRASHED

The recovery manager sees the Redo logs and inspect the transaction U is committed or not. Such changes made by transaction U are reached to disk.

• So much the recovery manager arranged the elements to their recent values changed by transaction U.

• Transaction U changed the elements B and its records <U, B, 20>with re-cent values.

• Transaction U changed the elements D and its records <U, D, 40>with recent values.

• The transaction T is not committed.

• Then the elements changed by transaction T are arranged to old values.

• Then element A is arranged to 10, C is arranged to 30 and E is arranged to 50.

7 0
2 years ago
Lin is booting up his computer, and during the boot process, the computer powers down. After several unsuccessful attempts to bo
mel-nik [20]

Answer:

The RAM Modules.

Explanation:

If the power supply is working properly, the next thing that could cause an auto-shutdown could be the RAM.

Sometimes static electricity,  a faulty slot, or even a faulty memory module  could be causing the RAM to fail. And as the OS needs to read from the RAM in order to boot, at the moment the processor can't find the RAM information, it shuts down the system.

Changing the RAM modules to a different slot, switching slots, or cleaning the memory module pins with a regular eraser can help solve the problem. If not, then Lin might need to buy a new module, or keep going forward with the diagnostic process.

3 0
2 years ago
Consider a disk that rotates at 3600 rpm. The seek time to move the head between adjacent tracks is 2 ms. There are 32 sectors p
jasenka [17]

Answer:

19.71 ms

Explanation:

The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.

Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms

Head movement time from track 8 to track  9 = seek time = 2 ms

rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms

The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms

3 0
2 years ago
B.) Define latency and jitter for service flow in a fixed wireless system.
yuradex [85]
The answer would be between the base station and the subscriber station.
7 0
2 years ago
4.17 LAB: Data File A comma separated value (.csv) file has been included to be used for this program. Each line contains two va
Andrej [43]

Answer:

import csv

def Csvreader(filename):

   with open("filename", "r") as file:

   content = file.csv_reader()

   list_content = list(content)

   file.close

   return list_content

Explanation:

This is a python description of the function that reads the csv file and converts it to a list, from the list, each item can accessed with its index and updated directly. Use this to draw the same conclusion for a java program.

7 0
2 years ago
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