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sweet-ann [11.9K]
2 years ago
12

Given an integer variable strawsOnCamel, write a statement that uses the auto-increment operator to increase the value of that v

ariable by 1.
Computers and Technology
1 answer:
Reptile [31]2 years ago
5 0

Answer:

The program to this question can be given as follows:

Program:

#include <stdio.h> //include header file for using basic function

int main() //defining main method

{

int strawsOnCamel=0; //defining integer variable and assign value

for(int i=1;i<=5;i++) //loop for increment integer variable value

{

//code

strawsOnCamel++; //increment value by 1

printf("%d\n", strawsOnCamel); //print value

}

return 0;

}

Output:

1

2

3

4

5

Explanation:

In the C language code above the header file is entered, and a whole variable strawsOnCamel is specified within the main method, which gives a value of 0.

  • Then a for loop is defined inside a loop an integer variable i declared that starts from 1 and ends with 5.
  • Inside a loop, the strawsOnCamel variable is used that increments its value by 1 and prints its value.

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Define a structure type auto_t to represent an automobile. Include components for the make and model (strings), the odometer rea
yulyashka [42]

Answer:

see explaination

Explanation:

#include <stdio.h>

#include <string.h>

#define BUFSIZE 1000

struct auto_t scan_auto(char *);

struct date_t {

char day[2];

char month[2];

char year[4];

};

struct tank_t {

char tankCapacity[10];

char currentFuelLevel[10];

};

struct auto_t {

char make[50];

char model[50];

char odometerReading[10];

struct date_t manufactureDate;

struct date_t purchaseDate;

struct tank_t gasTank;

};

int main(int argc, char *argv[]) {

/* the first command-line parameter is in argv[1]

(arg[0] is the name of the program) */

FILE *fp = fopen(argv[1], "r"); /* "r" = open for reading */

char buff[BUFSIZE]; /* a buffer to hold what you read in */

struct auto_t newAuto;

/* read in one line, up to BUFSIZE-1 in length */

while(fgets(buff, BUFSIZE - 1, fp) != NULL)

{

/* buff has one line of the file, do with it what you will... */

newAuto = scan_auto(buff);

printf("%s\n", newAuto.make);

}

fclose(fp); /* close the file */

}

struct auto_t scan_auto(char *line) {

int spacesCount = 0;

int i, endOfMake, endOfModel, endOfOdometer;

for (i = 0; i < sizeof(line); i++) {

if (line[i] == ' ') {

spacesCount++;

if (spacesCount == 1) {

endOfMake = i;

}

else if (spacesCount == 2) {

endOfModel = i;

}

else if (spacesCount == 3) {

endOfOdometer = i;

}

}

}

struct auto_t newAuto;

int count = 0;

for (i = 0; i < endOfMake; i++) {

newAuto.make[count++] = line[i];

}

newAuto.make[count] = '\0';

count = 0;

for (i = endOfMake+1; i < endOfModel; i++) {

newAuto.model[count++] = line[i];

}

newAuto.model[count] = '\0';

count = 0;

for (i = endOfModel+1; i < endOfOdometer; i++) {

newAuto.odometerReading[count++] = line[i];

}

newAuto.odometerReading[count] = '\0';

return newAuto;

}

8 0
2 years ago
Given an n-element array X, algorithm D calls algorithm E on each element X[i]. Algorithm E runs in O(i) time when it is called
krek1111 [17]

Answer:

O(n^2)

Explanation:

The number of elements in the array X is proportional to the algorithm E runs time:

For one element (i=1) -> O(1)

For two elements (i=2) -> O(2)

.

.

.

For n elements (i=n) -> O(n)

If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)  

5 0
2 years ago
Together with some anthropologists, you’re studying a sparsely populated region of a rainforest, where 50 farmers live along a 5
Varvara68 [4.7K]

Answer:

Explanation:

Farmers are always both directly and indirectly connected to each other

Their network is mostly strong

Networks become weak only on the edges (ends) of the river but doesn't completely dimnish

With the available network length, the center of river bank forms the strongest network of all and becomes a key player in defining the balance property of overall network

The network is very well structurally balanced and we can see that through the below image

20 miles 10 20 30 40 50

See attachment file for diagram

Considering the total length of river as 50miles and and the center of the whole length will be at 25th mile. From that point, if we consider a farmer will be be having friends for a length of 20miles both along upstream and downstream.

By this he'll be in friend with people who are around 80% of the total population. As me move from this point the integrity increases and this results in a highly balanced structural network.

6 0
2 years ago
Jupiter Inc., a software firm, is starting to face competition from the new entrant in its market, Coral Inc. Jupiter wants to p
Scilla [17]

Answer:

A.

Explanation:

Based on the information provided within the question it can be said that in this scenario, Jupiter's best move would be to adopt the measure of ensuring that customers find its software simpler and more convenient to use than that of Coral. This would create satisfaction among the customers which in term would lead to customer loyalty.

8 0
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Which of the following is not one of the four criteria for evaluating websites?
Flura [38]

Answer:validity

Explanation:

Because it dont sound right

5 0
2 years ago
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