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2 years ago

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Arrays are described as immutable because they are two dimensional. are arranged sequentially. can be reordered. cannot be chang

ed once they are defined.

Computers and Technology

1 answer:

Vlada [557]2 years ago

6 0

Answer:

Arrays are described as immutable because they cannot be changed once they are defined. (D on Edge)

Explanation:

It's in the notes and I just took the test (2020)

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What data unit is encapsulated inside a packet?<br> frame<br> datagram<br> segment<br> session

AVprozaik [17]

The answer is frame

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2 years ago

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Lin is booting up his computer, and during the boot process, the computer powers down. After several unsuccessful attempts to bo

inysia [295]

Answer:

Option (c) is the correct answer of this question.

Explanation:

RAM (Random Access Memory) It is a type of computer memory which can also be retrieved and adjusted in either sequence, usually still had to preserve operating memory and bytecode.

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Other options are not related to the given scenario.

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2 years ago

With Voice over Internet Protocol (VoIP), _____. a. voicemails cannot be received on the computer b. call quality is significant

Pachacha [2.7K]

Answer:

c. Users can have calls forwarded from anywhere in the world

Explanation:

As all you need is the internet, there would be no need to try to sort out roaming as you would on a regular phone line

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2 years ago

In this lab, you use the pseudocode in figure below to add code to a partially created Python program. When completed, college a

Elza [17]

Answer:

Python code is given below with appropriate comments

Explanation:

#Prompt the user to enter the test score and class rank.

testScore = input()

classRank = input()

#Convert test score and class rank to the integer values.

testScore = int(testScore)

classRank = int(classRank)

#If the test score is greater than or equal to 90.

if(testScore >= 90):

#If the class rank is greater than or equal to 25,

#then print accept message.

if(classRank >= 25):

print("Accept")

#Otherwise, display reject message.

else:

print("Reject")

#Otherwise,

else:

#If the test score is greater than or equal to 80.

if(testScore >= 80):

#If class rank is greater than or equal to 50,

#then display accept message.

if(classRank >= 50):

print("Accept")

#Otherwise, display reject message.

else:

print("Reject")

#Otherwise,

else:

#If the test score is greater than or equal to

#70.

if(testScore >= 70):

#If the class rank is greater than or equal

#to 75, then display accept message.

if(classRank >= 75):

print("Accept")

#Otherwise, display reject message.

else:

print("Reject")

#Otherwise, display reject message.

else:

print("Reject")

4 0

2 years ago

Create a single list that contains the following collection of data in the order provided:

ivann1987 [24]

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

8 0

2 years ago