#include <stdio.h>
int main(void) {
// your code goes here
//unsigned a =float_times_four(0x80000000);
unsigned float_times_four(unsigned uf){
unsigned expn = (uf >> 23) & 0xFF;
printf(expn);
unsigned sign = uf & 0x80000000;
unsigned frac = uf & 0x007FFFFF;
if(expn == 255 ||(expn == 0 && frac ==0))
return uf;
if(expn){
expn<<2;
}else if(frac == 0x007FFFFF){
//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute
frac>>2;
expn<<2;
}else{
frac<<=2;
}
return (sign) | (expn <<23) | (frac);
}
return 0;
}
Answer:
Explanation:
We can use for-loop in python to calculate the tuition amount in the next 5 years. If the tuition is increasing 3% each year, in each loop we can multiply the amount by 1.03
tuition = 8000
for year in range(1,6):
tuition *= 1.03
print("The tuition amount after " + str(year) + " year(s) is $" + str(tuition))
Additional resource needed for the projects
Additional time needed for the project
<u>Explanation:</u>
In any project handing their will expected diversion and add on requirement, so to complete a project additional time and additional resource is required to finish a project.
As advice due the project details, end user has keep enough buffer for deviations on resource of man power and additional times taken to finish the project.
While design the project each scope of work is measure with additional time to complete the task
Each scope of work is considered as task in project management.
True.
Data processing involves the conversion of raw data and the flow of data through the Central Processing Unit and Memory to output devices. Each CPU in a computer contains two primary elements: the Arithmetic Logic Unit (ALU) and the control unit. The Arithmetic Logic Unit performs complex mathematical calculations and logical comparisons. On the other hand, the control unit accesses computer instructions, decodes them, and controls the flow of data in and out of the Memory, ALU, primary and secondary storage, and various other output devices.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
