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kati45 [8]
2 years ago
9

The processing of data in a computer involves the interplay between its various hardware components.

Computers and Technology
1 answer:
Ronch [10]2 years ago
8 0

True.

Data processing involves the conversion of raw data and the flow of data through the Central Processing Unit and Memory to output devices. Each CPU in a computer contains two primary elements: the Arithmetic Logic Unit (ALU) and the control unit. The Arithmetic Logic Unit performs complex mathematical calculations and logical comparisons. On the other hand, the control unit accesses computer instructions, decodes them, and controls the flow of data in and out of the Memory, ALU, primary and secondary storage, and various other output devices.  


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Identify the correct language concept or term from the drop-down menu. A Programming Language is a language that physically runs
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Answer and Explanation:

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There are many different types of hardware devices, different manufacturers, and countless configuration possibilities. Explain
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Because, they are all required to configure to it to be recognized by an operating system.

Explanation:

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Example.

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FOREACH, EXPLODE and MAIL are examples of crazy functions.
jenyasd209 [6]
The answer would be B
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When this program is compiled and executed on an x86-64 Linux system, it prints the string 0x48\n and terminates normally, even
Alexxandr [17]

Answer:

I get 0x55 and this the linking address of the main function.

use this function to see changes:

/* bar6.c */

#include <stdio.h>

char main1;

void p2()

{

printf("0x%X\n", main1);

}

Output is probably 0x0

you can use your original bar6.c with updaated foo.c

char main;

int main() // error because main is already declared

{

  p2();

   //printf("Main address is 0x%x\n",main);

  return 0;

}

Will give u an error

again

int main()

{

  char ch = main;

  p2(); //some value

  printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()

  printf("Char value is 0x%x\n",ch); //last two digit of previous line output

  return 0;

}

So the pain in P2() gets the linking address of the main function and it is different from address of the function main.

Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...

Explanation:

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First, open two separate terminal connections to the same machine, so that you can easily run something in one window and the ot
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