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2 years ago

What is a commonly publicized password sql injection string?

1 answer:

7 0

The strings "or 1=1" and ""or ''=''" can be commonly used to trick an SQL WHERE clause into becoming true.

So if you specify ' or ''=' as a password, you can log in if the query string would be:

select username,pass from users where username='you' and password='' or ''='' limit 0,1;

You might be interested in

Which data type change will require the app builder to perform the additional steps in order to retain existing functionalities?

Readme [11.4K]

Answer:

Option D is the correct option.

Explanation:

The following option is correct because the lead alteration from number to text and the number to text types of data will reconstruct the important number of the app builder to accomplish those steps which is extra to continue to have that functionality which is in the existence. That's why the app builder has to be reconstructed the types of data for the custom fields.

7 0

1 year ago

Your company wants to conduct an exploratory study to gain new insights into some product changes you are considering. Which typ

Lina20 [59]

Answer: Primary Research (Focus Group).

Explanation:

Exploratory Research is an inquiry that seeks to understand the basic causal factors of a problem. This effort can serve as the basis of more intensive research later on.

There are basically two methodologies used, which are the; Primary and Secondary methods. While the Primary method's source of information is the concerned group, the Secondary Methods obtain their information from already existing information (Primary sources), such as Interviews, Journals, etc.

In the case of the company in the question, seeking to gain insight into the changes in a product, it would be best for them to consider what some selected costumers (focus group), think about the existing products and their views on subsequent changes. This method of getting information directly from the focus group employs the primary method.

3 0

1 year ago

Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:

horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0

1 year ago

Acceleration is the rate at which an object changes its velocity. It is typically represented by symbol a and measured in m/s2 (

Natalija [7]

Answer:

Pseudocode:

INPUT velocity

INPUT time

SET velocity = 0.44704 * velocity

SET acceleration = velocity / time

SET acceleration = round(acceleration, 1)

PRINT acceleration

Code:

velocity = float(input("Enter a velocity in miles per hour: "))

time = float(input("Enter a time in seconds: "))

velocity = 0.44704 * velocity

acceleration = velocity / time

acceleration = round(acceleration, 1)

print("The acceleration is {:.2f}".format(acceleration))

Explanation:

*The code is in Python.

Ask the user to enter the velocity and time

Convert the miles per hour to meters per second

Calculate the acceleration using the formula

Round the acceleration to one decimal using round() method

Print the acceleration with two decimal digits

7 0

1 year ago

When should a developer begin thinking about scalability? 1 during the design phase 2during testing 3when traffic increases by 2

Tanzania [10]

Answer:

in my opinion 4

Explanation:

when the system is available to users

(sorry and thanks)

4 0

1 year ago