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stiks02 [169]
2 years ago
11

Greengage, Inc., a successful nursery, is considering several expansion projects. All of the alternatives promise to produce an

acceptable return. Data on four possible projects follow:
Project Expected Return Range Standard deviation
A 12.0% 4.0% 2.9%
B 12.5 5.0 3.2
C 13.0 6.0 3.5
D 12.8 4.5 3.0

A. Which project is least risky, judging on the basis of range?
B. Which project has the lowest standard deviation? Explain why standard deviation may not be an entirely appropriate measure of risk for pusrposes of this comparison.
C. Calculate the coefficient of variation for each project. Which project do you think Greengage's owners should choose? Explain why?
Business
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

A. Project A

B. Project A has lowest Standard Deviation

C. Project D

Explanation:

A.

The higher the range, the more risky the project is. Based on the table, project A has the smallest range, and therefore is the least risky based on range.

B.

The standard deviation is not scale-free, i.e. it is not adjusted for the level of returns. Hence, a project that has the same distribution of returns, but a higher average return, will have a higher standard deviation. But the project is not any more risky. Hence, the standard deviation might not be an appropriate measure of risk.

C.

The Coefficient of Variation (CV) is calculated as follows:

CV = Standard deviation / expected return

Applying this formula, the coefficient of variation for each project is:

Project A: 2.9% / 12.0% = 0.242

Project B: 3.2% / 12.5% = 0.256

Project C: 3.5% / 13.0% = 0.269

Project D: 3.0% / 12.8% = 0.23 4

Based on the coefficient of variation, project D has the lowest coefficient. It means that the project has the lowest risk per unit of return generated, and thus is the best project and should be chosen.

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A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Klio2033 [76]

Answer:

Side opposite the river = 120 ft

Other sides = 240 ft

Explanation:

Let 'R' denote the length of fence opposite to the river and 'L' denote the length of the other two sides.

The cost as a function of R is:

L*R = 28,800\\L=\frac{28,800}{R}\\ C = 40R+10*2*\frac{28,800}{R} \\C(R) = 40R+576,000R^{-1}

The value of R for which the derivate of the cost function is zero is the length that minimizes cost:

C'(R) =0= 40 -576,000R^{-2}\\R=\sqrt{\frac{576,000}{40}}\\R=120\ ft\\

If R is 120 ft, then the value of L is:

L = \frac{28,800}{120}\\L=240\ ft

The dimensions that will minimize costs are:

Side opposite the river = 120 ft

Other sides = 240 ft

5 0
2 years ago
Keys Printing plans to issue a $1,000 par value, 20-year noncallable bond with a 7.00% annual coupon, paid semiannually. The com
sveticcg [70]

Answer:

option b) -0.35%

Explanation:

For tax rate = 40%

After after-tax cost of debt = cost of debt × ( 1 - Rate )

= 7% × ( 1 - 0.40 )

= 4.20%

For tax rate = 45%

After after-tax cost of debt = cost of debt × ( 1 - Rate )

= 7% × ( 1 - 0.45 )

= 3.85%

Therefore, the change in cost of debt = 3.85% - 4.20% = -0.35%

Hence,

Correct answer is option b) -0.35%

3 0
2 years ago
A chemical manufacturer is setting up capacity in Europe and North America for the next three years. Annual demand in each marke
Yuri [45]

Answer:

Explanation:

The two choices under consideration are building 4 million units of capacity in North America

YEAR                         1                    2                           3  

Production and Sales 4,000,000.00   4,000,000.00   4,000,000.00  

Variable cost @ 10  40,000,000.00   40,000,000.00   40,000,000.00  

Divide by:

Conversion Factor  1.33                         1.33                     1.33  

Multiply by:

Growth(.1*.5)+(-.05*.5) 1.025                        1.025^2                  1.025^3  

NET CASHFLOWS  30,827,068.00   31,597,744.00   32,387,688.00  

DCF @ 10%     0.909090909           0.83                  0.75  

Present Values  28,024,607.27   26,113,838.02   24,333,349.36  

NET TOTAL COST 78,471,794.65  

or building 2 million units of capacity in each of the two loca-tions. Building two plants will incur an additional one-time cost of $2 million.

YEAR                  0            1                      2                              3  

Production and Sales       4,000,000.00      4,000,000.00   4,000,000.00  

Variable cost @ [(10+9)/2] 38,000,000.00  38,000,000.00   38,000,000.00  

Additional cost  2,000,000.00      

Conversion Factor     1.33     1.33                   1.33                       1.33  

Growth(.1*.5)+(-.05*.5)    1.025               1.025^2              1.025^3  

CASHFLOWS  1,503,759.40  29,285,714.29  30,017,857.00  30,768,304.00  

DCF @ 10%       1           0.909090909    0.826446281 0.751314801  

Present Value 1,503,759.40  26,623,376.62   24,808,146.28   23,116,682.19  

NET TOTAL COST = 76,051,964.50  

DECISION: The manufacturer should build 2 plants in 2 different locations because it gives a lower net present cost

<u>At what initial cost differential from building the two plants will the chemical manufacturer be indifferent between the two options?</u>

The difference in both options came from the fact that variable cost is lower in Europe and building the plant is more expensive. If there is no increase in cost and variable cost is same everywhere, then both options will be same.

5 0
2 years ago
A boat-cleaning company needs to increase its number of clients. It walks through segmentation and targeting exercises and disco
sertanlavr [38]

Marketing of a boat cleaning company needs to account for targeting a segment of population that owns boats.

Explanation:

Here, in simple terms, the marketing strategy is missing the people it was supposed to target for their marketing.

The company working in the niche has to target boat owners specifically, which the marketing fails to do.

<u>Segmentation is an activity in which a wide net of marketing population is marketed to and then the clients are filtered out.</u> This is not a very effective method but it was essentially trying to <u>find which people look out for the service the company provides.</u>

5 0
2 years ago
Read 2 more answers
1. How much interest would you pay on a loan of $1,230 for 15 months at 15 percent APR if the interest is 18.75 per $100?
Alina [70]
1. How much interest would you pay on a loan of $1,230 for 15 months at 15 percent APR if the interest is 18.75 per $100?


 The chart probably refers to interest per $100 of loan. So, the interest for a $1,230 loan would be (1230/100) * 18.75 = 230.625 ~ 230.63
So, the answer will be B $230.63.


2. Sherri borrowed $3,200 at 13 percent APR for 18 months. If she must pay 19.5 per $100, what is the total interest?
3,200 / 100 = 32 ... x 19.5 = 624 
Principal x int rate x time = 3200 x .13 x 1.5 yr = 624 interest

So, the answer will be the A $624.


3. What is the total amount that Sherri (in question number 2) will repay?

The correct answer will be the $3,824.


7 0
2 years ago
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