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joja [24]
1 year ago
12

Multiply Express your answer in simplest form Next

Mathematics
1 answer:
siniylev [52]1 year ago
3 0

Answer:

guess what it is..................

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Harry's soccer team is trying to raise $2520 to travel to a tournament in Florida, so they decided to host a pancake breakfast.
Serggg [28]

Answer: 168 people have to attend

Step-by-step explanation: 2520÷15= 168...just divide it to get it, if it help pls mark as brainliest ^-^, Thank you!

7 0
1 year ago
A portfolio consisting of four stocks is expected to produce returns of minus9%, 11%, 13% and 17%, respectively, over the next f
anastassius [24]

Answer:

standard deviation of these expected returns = 0.0295 or 2.95%

Step-by-step explanation:

The detailed step is shown in the attachment

8 0
1 year ago
Jayden has some dimes and some quarters. He has at most 25 coins worth at least $4.60 combined. If Jayden has 7 dimes, determine
Y_Kistochka [10]

Answer:

Step-by-step explanation:

A dime is worth 10 cents. Converting to dollars, it becomes 10/100 = $0.1

A quarter is worth 25 cents. Converting to dollars, it becomes 25/100 = $0.25

Let x represent the number of dimes that Jayden has.

Let y represent the number of quarters that Jayden has.

Jayden has some dimes and some quarters. He has at most 25 coins. It means that

x + y ≤ 25

The coins worth at least $4.60 combined. It means that

0.1x + 0.25y ≥ 4.6 - - - - - - - - - - 1

If Jayden has 7 dimes, then

7 + y ≤ 25

y ≤ 25 - 7

y ≤ 18

Substituting x = 7 into equation 1, it becomes

0.1 × 7 + 0.25y ≥ 4.6

0.7 + 0.25y ≥ 4.6

0.25y ≥ 4.6 - 0.7

0.25y ≥ 3.9

y ≥ 3.9/0.25

y ≥ 15.6

All possible values for the number of quarters that he could have would be

15.6 ≤ y ≤ 18

6 0
1 year ago
At middle Avenue school, 1/30 of the students are on track team. The track coach offered to buy pizza or subs for everyone on th
atroni [7]
3/5 of the students ate pizza
4 0
1 year ago
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
1 year ago
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