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Ivenika [448]
2 years ago
14

Let's say that you handle the IT systems administration for your company. There's a server inside of your organization that chec

ks how often client machines access it. If a client machine hasn't accessed the server in three months, the server won't allow the client machine to access its resources anymore. What can you set to make sure that your client machines and the server times are in sync?
Computers and Technology
1 answer:
kirill115 [55]2 years ago
7 0

From server do some file transfer to client PC to sync to the server.

<u>Explanation:</u>

As IT System administrator if PC or client or workstation or laptop not connected to network more than 3 months from windows server we need to refresh the connection and redo the connection from server to the client to do sync the activities.

Moreover from domain server refresh and re sync activities to establishing the connection.

Go to client PC or workstation or desktop login log and logout from the PC and login to domain account by changing the password.

You might be interested in
Printers produce _____ output. Displays produce _____ output. A _____ is an audio output device that converts text to speech. Ma
sesenic [268]

Answer:

"Hard copy", "Soft copy", "voice synthesizer", "flat panel", "projector".

Explanation:

  1. The above-defined words will fill the above blanks. Then the above sentence above below meanings:-
  2. The hard copy is ab printed form of soft copy which is generated by the printer device.
  3. The soft copy is displayed on the monitor screen.
  4. The voice synthesizer is used to convert the text onto a speech.
  5. The flat-panel device has a low volume and weight. There is much display which is in this type.
  6. The projector is used to display on the wall.
8 0
2 years ago
ArgumentException is an existing class that derives from Exception; you use it when one or more of a method’s arguments do not f
dybincka [34]

Answer:

The C# code is given below

Explanation:

using System;

public class SwimmingWaterTemperatur

{

public static void Main()

{

while(true){

Console.Write("\nPlease enter the water temperature : ");

int x = Int32.Parse (Console.ReadLine());

try{

if(CheckComfort(x)){

Console.Write(x+" degrees is comfortable for swimming.");

}else{

Console.Write(x+" degrees is not comfortable for swimming.");

}

}catch(Exception ex){

Console.WriteLine(ex);

}

}

}

public static Boolean CheckComfort(int temp){

if(temp>=70 && temp<=85){

return true;

}else if(temp>=32 && temp<=212){

return false;

}else{

throw new ArgumentException("Value does not fall within the exptected range.");

}

}

}

7 0
2 years ago
Write a copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *thi
ollegr [7]

Answer:

Here is the copy assignment operator for CarCounter:

CarCounter& CarCounter::operator=(const CarCounter& objToCopy) {

carCount = objToCopy.carCount;

return *this;  }

The syntax for copy assignment operator is:

ClassName& ClassName :: operator= ( ClassName& object_name)

In the above chunk of code class name Is CarCounter and object name is objToCopy.

Assignment operator = is called which assigns objToCopy.carCount to the new objects's carCount.

This operator basically is called when an object which is already initialized is assigned a new value from another current object.

Then return *this returns the reference to the calling object

Explanation:

The complete program is:

#include <iostream>  //to use input output functions

using namespace std;   //to access objects like cin cout

class CarCounter {  //class name

public:  // public member functions of class CarCounter

CarCounter();  //constructor of CarCounter

CarCounter& operator=(const CarCounter& objToCopy);  //copy assignment operator for CarCounter

void SetCarCount(const int setVal) {  //mutator method to set the car count value

carCount = setVal;  } //set carCount so setVal

int GetCarCount() const {  //accessor method to get carCount

return carCount;  }  

private:  //private data member of class

int carCount;  };    // private data field of CarCounter

CarCounter::CarCounter() {  //constructor

carCount = 0;  //intializes the value of carCount in constructor

return; }  

// FIXME write copy assignment operator  

CarCounter& CarCounter::operator=(const CarCounter& objToCopy){

/* copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *this */

carCount = objToCopy.carCount;

return *this;}  

int main() {  //start of main() function

CarCounter frontParkingLot;  // creates CarCounter object

CarCounter backParkingLot;   // creates CarCounter object

frontParkingLot.SetCarCount(12);  // calls SetCarCount method using object frontParkingLot to set the value of carCount to 12

backParkingLot = frontParkingLot;  //assigns value of frontParkingLot to backParkingLot

cout << "Cars counted: " << backParkingLot.GetCarCount();  //calls accessor GetCarCount method to get the value of carCount and display it in output

return 0;  }

The output of this program is:

Cars counted = 12

3 0
2 years ago
Consider whether there are additional components that could be added to the IPv4 protocol to enhance its usefulness. What are th
geniusboy [140]

Answer:

There are no additional components that can be added to the IPv4 protocol to improve its utility

Explanation:

The IPv4 protocol was developed in 1983 and is still the most widely used version worldwide. It consists of a 32-bit binary number that is normally represented in decimal notation, with four digits separated by dots that take values between 0 and 255.

This system limits the IPv4 protocol to 4,000 million different addresses, a figure that in the eighties seemed sufficient but that in practice has been scarce due to the revolution of mobile devices and the impending development of the Internet of Things ( IoT) that will trigger the number of devices connected to the network.

So, there are no additional components that can be added to the IPv4 protocol to improve its utility, since the world is running out of IPv4 addresses and is being replaced by IPv6.

Hope this helps!

5 0
2 years ago
What is the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz? Group of answer choices
denpristay [2]

Answer:

15.420 dB

Explanation:

the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz is 15.420 dB.

3 0
2 years ago
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