Answer:
After one second, 130 ft
After two second , 60 ft
Step-by-step explanation:
Both boats are moving towards each other,
Speed of first boat = 40 ft/min.
Speed of second boat = 30 ft/min.
So, In one Second they must have covered a total distance of 40 + 30 ft
= 70 ft.
Total width of the lake = 200 ft
So, Distance remained between them after one second = 200 - 70 = 130 ft.
After two seconds , First boat will move my 80 ft and second one will move by 60 ft
So, distance between them will decrease by 140 ft.
Distance between the boats after two seconds = 60 ft.
Answer:
f(x + 1) = 3x² + 5x + 7
Step-by-step explanation:
To find f(x + 1), substitute x = x + 1 into f(x), that is
f(x + 1) = 3(x + 1)² - (x + 1) + 5 ← expand (x + 1)² using FOIL
= 3(x² + 2x + 1) - x - 1 + 5 ← distribute parenthesis by 3
= 3x² + 6x + 3 - x - 1 + 5 ← collect like terms
= 3x² + 5x + 7
110/50=2.2 (each person consumes 2.2 kg of rice)
50+20 (the people who join)=70 total of people
70X2.2= 154 kg of rice.
X+y=425. This is as simple it can be, unless theres more information. x is the distance traveled on the first day and y is the distance traveled on the second day.
