A = (1/2) * b * h
The base is 10; the x-value going from 0 to 10.
The perpendicular height is 2; the y-value going from 0 to 2
A = (1/2) * 10 * 2
A = 10 units ^2
Answer:
11.25
Step-by-step explanation:
sketch a triangle and fill in the sides,add the sides and equate to 180, collect the like terms to get the value of x=11.25
Answer:
Cov(X, Y) =0.029.
Step-by-step explanation:
Given that :
The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)
Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.
0.04e–jτj/10 ............(2)
Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.
That is, they are 5 seconds apart,
τ = 5 seconds..............(3)
Thus,
Cov(X, Y), for τ = 5seconds = 0.04e-5/10
= 0.04e-0.5 = 0.04/√e
= 0.04/1.6487
= 0.0292
Thus, Cov(X, Y) =0.029.
Answer:
<h3>Add 47.6 and 39.75, then round the answer</h3>
Step-by-step explanation:
If Ramina found the length of two pieces of ribbon to be 47.6 inches and 39.75 inches, the effective strategy of finding the sum of the two lengths is to:
1) First is to add the two values together
47.6 + 39.75
= (47+0.6)+(39+0.75)
= (47+39)+(0.6+0.75)
= 86 + 1.35
= 87.35
2) Round up the answer to nearest whole number.
87.35 ≈ 87 (note that we couldn't round up to 88 because the values after the decimal point wasn't up to 5)
Option C is correct
Answer:
The answer is 1/3 or 0.33
Step-by-step explanation:
Let's consider the following ocurrences:
A: A person has a MasterCard
B: A person has an American Express
The data says:
P(A∩B) = 0.2
P(A without B) = 0.4
P(B without A) = 0.1
Then, P(A) = P(A∩B) +P(A without B) = 0.2+0.4 = 0.6
By conditional probability theory:
P (B/A) = P(A∩B) / P(A) = 0.2 / 0.6 = 1/3 = 0.33
Thus
P(B/A) = 1/3 = 0.33
