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iogann1982 [59]
2 years ago
5

Sue Jones is insured for bodily injury in the amount of 10/20. She is at fault in an accident in which Albert Smith is injured.

Also injured in the accident is a pedestrian, Sam Dickson. Albert's medical expenses total $12,000, Sam's come to $8,000. How much will the insurance pay? a. for Albert b. for Sam c. total
Mathematics
2 answers:
lianna [129]2 years ago
4 0
For this case, what you should know is that Sue Jones insurance covers half of the expenses. Equivalently, her insurance covers:
 10/20 = 1/2 = 0.5
 Therefore, we have then that
 a. for Albert 
 0.5 * (12000) = $ 6000
 b. for Sam 
 0.5 * (8000) = $ 4000
 c. total
 The sum of the results of parts a and b
 $ 6000 + $ 4000 = $ 10,000
 answer
 $ 6000
 $ 4000
 $ 10,000
musickatia [10]2 years ago
4 0

Answer:

Albert is $12,000

Sam is $8,000

So in total it would be $20,000

Step-by-step explanation:

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According to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market. A random sample of 70 users
Natalija [7]

Answer:

Probability that 32 or more from this sample used Internet Explorer as their browser is 0.9015.

Step-by-step explanation:

We are given that according to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market.

A random sample of 70 users was selected.

Let \hat p = <u><em>sample proportion of users who used Internet Explorer as their browser.</em></u>

The z score probability distribution for sample proportion is given by;

                            Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, p = population proportion of users who use internet explorer = 53.4%

           \hat p = sample proportion = \frac{32}{70} = 0.457

           n = sample of users = 70

Now, probability that 32 or more from this sample used Internet Explorer as their browser is given by = P( \hat p \geq 0.457)

      P( \hat p \geq 0.457) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } \geq \frac{0.457-0.534}{\sqrt{\frac{0.457(1-0.457)}{70} } } ) = P(Z \geq -1.29)

                            = P(Z \leq 1.29) = <u>0.9015</u>

The above probability is calculated by looking at the value of x = 1.29 in the z table which has an area of 0.9015.

4 0
2 years ago
A pair of fair dice is cast. what is the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one
WITCHER [35]
If a pair of fair dice is cast, the probability that the <span>sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is given by:

\frac{P(sum\, of\, 9\, \cup\,3)}{P(3)}

The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.

</span>The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.

Therefore, <span>the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.</span>
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3 x 1/6 in simplest form
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Im not sure but i thing its 0.5 or 1/2
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Their sum would be of odd number....
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