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iogann1982 [59]
2 years ago
5

Sue Jones is insured for bodily injury in the amount of 10/20. She is at fault in an accident in which Albert Smith is injured.

Also injured in the accident is a pedestrian, Sam Dickson. Albert's medical expenses total $12,000, Sam's come to $8,000. How much will the insurance pay? a. for Albert b. for Sam c. total
Mathematics
2 answers:
lianna [129]2 years ago
4 0
For this case, what you should know is that Sue Jones insurance covers half of the expenses. Equivalently, her insurance covers:
 10/20 = 1/2 = 0.5
 Therefore, we have then that
 a. for Albert 
 0.5 * (12000) = $ 6000
 b. for Sam 
 0.5 * (8000) = $ 4000
 c. total
 The sum of the results of parts a and b
 $ 6000 + $ 4000 = $ 10,000
 answer
 $ 6000
 $ 4000
 $ 10,000
musickatia [10]2 years ago
4 0

Answer:

Albert is $12,000

Sam is $8,000

So in total it would be $20,000

Step-by-step explanation:

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2 Points
hichkok12 [17]

Answer: 345.02

Step-by-step explanation:

8 0
2 years ago
Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif
Nadusha1986 [10]

Answer:

sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

Step-by-step explanation:

given is the Differential equation in I order linear as

y′+4y=48t,y(0)=9.

Take Laplace on both sides

L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}

Now if we take inverse we get y(t) the solution

Thus the algebraic equation would besY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

8 0
2 years ago
injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and ri
diamong [38]

Answer:

The length of the track is approximately 51.7 ft

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle.

5 0
2 years ago
A car with an initial cost of $23,000 is decreasing in value at a rate of 8% each year. Write the exponential decay function des
zlopas [31]

Answer:

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r/n)^ nt

Where

A represents the value after t years.

n represents the period for which the decrease in value is calculated

t represents the number of years.

P represents the value population.

r represents rate of decrease.

From the information given,

P = 23000

r = 8% = 8/100 = 0.08

n = 1

Therefore, the exponential decay function described in this situation is

A = 23000(1 - 0.08/n)1)^ 1 × t

A = 23000(0.92)^t

If A = 15000, then

15000 = 23000(0.92)^t

0.92^t = 15000/23000 = 0.6522

Taking log of both sides to base 10

Log 0.92^t = log 0.6522

tlog 0.92 = log 0.6522

- 0.036t = - 0.1856

t = - 0.1856/- 0.036

t = 5 years to the nearest year

3 0
2 years ago
A sample of the salaries of assistant professors on the business faculty at a local university revealed a mean income of $100,00
serg [7]

Answer:

a) 68%

b) 95%.

c) 2.5%

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 100,000, standard deviation of 10,000.

a. Approximately what percentage of the salaries fall between $90,000 and $110,000?

90,000 = 100,000 - 10,000

110,000 = 100,000 + 10,000

Within 1 standard deviation of the mean, so approximately 68%.

b. Approximately what percentage of the salaries fall between $80,000 and $120,000?

80,000 = 100,000 - 2*10,000

120,000 = 100,000 + 2*10,000

Within 2 standard deviations of the mean, so approximately 95%.

c. Approximately what percentage of the salaries are greater than $120,000?

More than 2 standard deviations above the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean, so approximately 5% are more than 2 standard deviations from the mean.

The normal distribution is symmetric, which means that 2.5% are more then 2 standard deviations below the mean, and 2.5% are more than 2 standard deviations above the mean, which means that 2.5% of the salaries are greater than $120,000.

7 0
2 years ago
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