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1 year ago

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A share of stock in a pharmaceutical company was worth $30.46 on Monday. On Wednesday, the stock price changed to $45.83. What i

s the net change in the stock price from Monday to Wednesday?

2 answers:

mestny [16]1 year ago

7 0

15.37 dollars. You get this answer by subtracting 45.83 minus 30.46

Usimov [2.4K]1 year ago

3 0

Looks to me like ur sales tax is 9% and ur instant rebate is 30 bucks

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A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10$

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

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1 year ago

Group of baseball fans can see home plate from a 40 meter tall building outside the stadium. The angle of vision has a tangent o

dimulka [17.4K]

Answer:

17.78 meters

Step-by-step explanation:

Let

x ----> the horizontal distance, in meters, to home plate

$\theta$ ----> the angle of vision

we know that

$tan(\theta)=\frac{40}{x}$ ----> by TOA (opposite side divided by the adjacent side)

we have

$tan(\theta)=\frac{9}{4}$

substitute

$\frac{9}{4}=\frac{40}{x}$

solve for x

$x=40(4)/9\\x=17.78\ m$

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Goodlife charges its members $30 per month for a gym membership. They currently have 75 clients.

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They should charge $40 per membership, and they will make a maximum revenue of $2400

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Given triangle GHJ, the measure of angle G equals 110°, the measure of angle J equals 40°, and the measure of angle H equals 30°

tester [92]

Answer:

Since angle G is

✔ the largest

angle, the opposite side, JH, is

✔ the longest side

. The order of the side lengths from longest to shortest is

✔ HJ, GH, and GJ

.

Step-by-step explanation:

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