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ElenaW [278]
2 years ago
15

Troy made a scale drawing of the Statue of Liberty which has an actual height of 305 feet. He decides to use a scale in which 1

inch represents 25 feet. What is the height in inches of troy's drawing
Mathematics
1 answer:
sergiy2304 [10]2 years ago
3 0

The height of statue is 12.2 inches in Troy's drawing.

Step-by-step explanation:

Given,

Actual height of statue = 305 feet

Scale used by Troy;

25 feet = 1 inch

1 feet = \frac{1}{25}\ inches

305 feet = \frac{1}{25}*305 \ inches

305 feet = \frac{305}{25}\ inches\\

305 feet = 12.2 inches

The height of statue is 12.2 inches in Troy's drawing.

Keywords: unit rate, division

Learn more about unit rate at:

  • brainly.com/question/884169
  • brainly.com/question/902892

#LearnwithBrainly

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Answer:

option C. Angle BTZ Is-congruent-to Angle BUZ

Step-by-step explanation:

Point Z is equidistant from the vertices of triangle T U V

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When ZT = ZV  ∴  ΔZTV is an isosceles triangle ⇒ ∠ZTV=∠ZVT

When ZU = ZV  ∴ ΔZUV is an isosceles triangle ⇒ ∠ZUV=∠ZVU

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And ∠BUZ is the same as ∠TUZ

So, the statement that must be true is option C

C.Angle BTZ Is-congruent-to Angle BUZ

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Answer:

The length of the track is approximately 51.7 ft

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

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Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

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