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Serga [27]
2 years ago
14

Suppose that 3 boys and 2 girls go to the theater and occupy 5 seats in a row. In how many ways can they be seated if all boys s

it together?
A-3
B-6
C-12
D-36
Mathematics
2 answers:
guajiro [1.7K]2 years ago
5 0
The answer to the problem is as follows:

Count all boys as one unit. Then there is one boy and 2 girls who can be permuted in 3! = 6 ways. Bout the 3 boys can permute among themselves in 3! = 6 ways.
 
<span>6x6 = 36 ways in which all boys are together.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Ede4ka [16]2 years ago
5 0
Hello there.

<span>Suppose that 3 boys and 2 girls go to the theater and occupy 5 seats in a row. In how many ways can they be seated if all boys sit together?

</span><span>D-36</span>
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The given options are:

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The key to determining which product is negative is to understand the rule of sign multiplication.

Now:

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