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1 year ago

8

Tomas is a commercial real estate agent who earns a yearly salary of $82,500 and a 2.5% commission on his total sales. If Tomas

sold properties that totaled $3.75 million in sales during one year, what are Tomas’s earnings for that year?

2 answers:

Georgia [21]1 year ago

7 0

Tomas earning is $176,250

Marianna [84]1 year ago

7 0

I think the correct answer 176258

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A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st

Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample credit hours per quarter = 15.2 credit hours

s = sample standard deviation = 2.3 credit hours

n = sample of students = 250

$\mu$ = population mean credit hours per quarter

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < $t_2_4_9$ < 1.96) = 0.95 {As the critical value of t at 249 degree of

freedom are -1.96 & 1.96 with P = 2.5%}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u><em>95% confidence interval for</em></u> $\mu$ = [ $\bar X-1.96 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $15.2-1.96 \times {\frac{2.3}{\sqrt{250} } }$ , $15.2+1.96 \times {\frac{2.3}{\sqrt{250} } }$ ]

= [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

<em>The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.</em>

8 0

1 year ago

The Hazell family has 4 children. Murphy is 1 year younger than his older brother Michael. Keira is 2 years younger than Murphy.

Allushta [10]

Isabelle is 7 years old

6 0

2 years ago

An upscale resort has built its circular swimming pool around a central area that contains a restaurant. The central area is a r

Elena L [17]

The problem is modelled in the diagram below

Question 1:
The largest area of the pool is half of the area of the circle

Area of circle = πr², where r is the radius given by 1/2 of the diameter
Area of circle = π(60)² = 11309.73355 feet

Area of half of the circle is 11309.73355/2 = 5654.866... ≈ 5654.87 feet (2dp)

Question b:

The area of the pool is the area of the circle subtracts the area of the triangle.

The area of the circle is 11309.73²

The area of the triangle is 1/2 (60×103.92) = 3117.6 feet²

The area of the pool is 11309.73 - 3117.6 = 7922.13 feet²

The volume of the pool = 7922.13 × 4 = 31688.52 feet³

Note: there isn't any information on the fish tank part so the answer above is assumed for the whole pool.

6 0

1 year ago

At time t=3, there are 2.5 cubic feet of water in the tub. Write an equation for the locally linear approximation of W at t=3, a

velikii [3]

Answer:

W=0.8333*t

2.917 ft³

Step-by-step explanation:

At time t=3, there is 2.5 ft³ of water in the tub

Finding the relation will be;

3=2.5

1=?

Rate=0.8333 ft³/min

W=0.8333 ft³ / min

W=0.8333*t

At t=3.5 will be;

1 min = 0.8333

3.5 min =?

Apply cross-production

3.5*0.8333 =2.917 ft³

4 0

2 years ago

Read 2 more answers

A scientist measures a substance to be 0.8 grams. Calculate the percent of error in the measurement. Show all work for full cred

Volgvan

You'll need to give a bit more information for the question to be answered. You can only calculate the percentage of error if you know what the mass of the substance *should be* and what you've *measured* it to be.

In other words, if a substance has a mass of 0.55 grams and you measure it to be 0.80 grams, then the percent of error would be:

percent of error = { | measured value - actual value | / actual value } x 100%

So, in this case:

percent of error = { | 0.80 - 0.55 | / 0.55 } x 100%
percent of error = { | 0.25 | / 0.55 } x 100%
percent of error = 0.4545 x 100%
percent of error = 45.45%

So, in order to calculate the percent of error, you'll need to know what these two measurements are. Once you know these, plug them into the formula above and you should be all set!

6 0

2 years ago