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kaheart [24]
2 years ago
10

Think about the function f(x) = 10 - x3. What is the input, or independent variable? f(x) x y What is the output, or dependent v

ariable or quantity? x f(x) y What does the notation f(2) mean? multiply f by 2 the output (y-value) when x = 2 the value of x when the output is 2 Evaluate f(2) =
Mathematics
3 answers:
k0ka [10]2 years ago
8 0
F(2) means function 2 f(2)=f(X))
Marizza181 [45]2 years ago
8 0

Answer:

x is the input, or independent variable and f(x) is the output, or dependent variable or quantity. f(2) represents the output (y-value) when x = 2. The value of f(2) is 2.

Step-by-step explanation:

If the values of a variable depends on the other variable, then it called dependent variable.

If the value of a variable does not depend on the other, then it is called independent variable.

If a function is f(x)=x, then x is an independent variable and f(x) is a dependent variable.

The given function is

f(x)=10-x^3

Here, x is the input, or independent variable and f(x) is the output, or dependent variable or quantity.

The notation f(a) represents the output (y-value) when x = a. So, f(2) represents the output (y-value) when x = 2.

Substitute x=2 in the given function.

f(2)=10-(2)^3

f(2)=10-8

f(2)=2

The value of f(2) is 2.

Guest11 months ago
0 0

GRAB AND GO ANSWERS:
1. B) x
2. B) f(x)
3. B) the output (y-value) when x=2
4. ANSWER IS 2

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Answer:

7.5 years

Step-by-step explanation:

P = $5000,

R = 4.25%,

A = $6593.75,

N =?

SI = A - P = 6593.75 - 5000 =$1593. 75

\because \: SI = \frac{ PNR}{100} \\  \\  \therefore \: 1593.75 =  \frac{5000 \times N \times 4.25}{100}  \\  \\  \therefore \: 1593.75 \times 100 = 21,250 \times N \\  \\ N =  \frac{159375}{21250}  \\  \\ N = 7.5 \: years \:

6 0
2 years ago
A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be
Andrei [34K]

Answer:

\$6,082.70  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$15,300\\r=14.25\%=0.1425\\x=6\ years

substitute in the formula

V=15,300(1-0.1425)^{6}  

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3 0
2 years ago
On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

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It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
1 year ago
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The answer is A I think
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kirill115 [55]
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5 0
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