Answer:
Range = [- 2.5, 0.5] = [ - 5/2, 1/2]
Step-by-step explanation:
Smallest value of cos α = - 1,
largest value of cos α = 1.
When cos 4x = - 1, y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5
When cos 4x = 1, y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5
Range = [- 2.5, 0.5] = [ - 5/2, 1/2]
Answer:
Therefore the value of tangent of ∠
is
°.
Step-by-step explanation:
Given that,
In Δ
, ∠
°,
and 
and we have to find the value of tangent of ∠
Diagram of the given triangle is shown below:
Now,
Δ
is a right angle triangle, so we can use all the trigonometric ratio.


= 
tangent of ∠
=
= 
= 
= 
∴∠
= 
=
° ≅
°
Therefore the value of tangent of ∠
is
°.
Answer:
Slope = rise / run
= -12 / 1500 (It's -12 and not 12 because a drop means it's decreasing)
= -0.008
Answer:
13
Step-by-step explanation:
The GCF of 36, 48, and 72 is 12 so there will be 36 / 12 = 3 stacks of English books, 48 / 12 = 4 stacks of science books and 72 / 12 = 6 stacks of math books for a total of 3 + 4 + 6 = 13 stacks.
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as

.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:



Now we can use the law of sines to find the distance

between Paul and Jose:



Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:

We can conclude that Jose is 33.9m from the base of the tree.