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guajiro [1.7K]
2 years ago
6

A jet flies at a rate of 1.3 * 10^6 feet per hour. Written in scientific notation, which is the best estimate of how many feet t

he jet will travel in 2.8 *10^3 hours?
Mathematics
2 answers:
kow [346]2 years ago
8 0

Answer:

C. 3x10^9

Step-by-step explanation:

FromTheMoon [43]2 years ago
3 0
To determine the distance covered by the jet in a given time, we simply multiply the rate or velocity of the jet to the time elapsed. It is important to take note of the units. It should be homogeneous. We calculate as follows:

1.3x10^6 x 2.8x10^3 = 3.64x10^9 ft

Hope this answers the question. Have a nice day.
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MariettaO [177]
Issa whole test my guy
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2 years ago
G identify the solution of the recurrence relation an = 6an − 1 – 8an − 2 for n ≥ 2 together with the initial conditions a0 = 4,
maksim [4K]
Via the generating function method, let

G(x)=\displaystyle\sum_{n\ge0}a_nx^n

Then take the recurrence,

a_n=6a_{n-1}-8a_{n-2}

multiply everything by x^n and sum over all n\ge2:

\displaystyle\sum_{n\ge2}a_nx^n=6\sum_{n\ge2}a_{n-1}x^n-8\sum_{n\ge2}a_{n-2}x^n

Re-index the sums or add/remove terms as needed in order to be able to express them in terms of G(x):

\displaystyle\sum_{n\ge2}a_nx^n=\sum_{n\ge0}a_nx^n-(a_0-a_1x)=G(x)-4-10x

\displaystyle\sum_{n\ge2}a_{n-1}x^n=\sum_{n\ge1}a_nx^{n+1}=x\sum_{n\ge1}a_nx^n=x\left(G(x)-a_0\right)=x(G(x)-4)

\displaystyle\sum_{n\ge2}a_{n-2}x^n=\sum_{n\ge0}a_nx^{n+2}=x^2\sum_{n\ge0}a_nx^n=x^2G(x)

So the recurrence relation is transformed to

G(x)-4-10x=6x(G(x)-4)-8x^2G(x)
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3 0
2 years ago
1) A 1.5 kg apple pie is sitting on the kitchen counter . If it has 13.44 J of gravitational potential energy, how tall is the c
vampirchik [111]

a)

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Explanation:

We know that,

P.E. = m g h

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P.E = Potential energy

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g = acceleration due to gravity (9.8 m/s²)

It is given that, m = 1.5 kg

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6 0
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almond37 [142]
M<P 59° is your answer
6 0
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