796,000/2388=10,000/x
796,000x= (2388*10,000)
796,000x/796,000=23,880,000/796,000
x=30 births
Answer:
Step-by-step explanation:
I use 84+ CE
stat edit, then fill in the #s
then
vars 5
then
2'nd stat plot, on
then, click stat
Click arrow 1 time to the left to get to Calc
then click (4)(LinReg(ax+b))
then click enter 5 times
(y=-25.31428571x+1000.285714
y=-25.3x+1000.3
now, lets use computer:
y=-25.31(543)+1000.3
y=-12743.03
round to the biggest whole number )
this doesn't really work, so I will put 1999, 2000, 2001, 2002, 2003, 2004 instead of 0, 1, 2, 3, 4, 5 and do the same thing
now I get
y=-25.31428571x+51603.54286
y=-25.3x+51603.5
now, lets use computer:
y=-25.3(543)+51603.5
y=37865.6
round to the biggest whole number:
y=37866
so, year 37866
You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:
9<em><u>0</u></em>5,154
To round 905,154 to the nearest ten-thousands place...
The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.
Since the 5 is greater than or equal to 5, we'll round our number up by
Adding 1 to the 0 in the ten-thousands place, making it a 1.
and by changing all digits to the right of this new 1 into zeros.
The result is: 910,000.
So, 905,154 rounded to the ten-thousands place is 910,000.
Answer: A. 1
Step-by-step explanation:
sorry if im wrong
Answer:
a: 28 < µ < 34
Step-by-step explanation:
We need the mean, var, and standard deviation for the data set. See first attached photo for calculations for these...
We get a mean of 222/7 = 31.7143
and a sample standard deviation of: 4.3079
We can now construct our confidence interval. See the second attached photo for the construction steps.
They want a 90% confidence interval. Our sample size is 7, so since n < 30, we will use a t-score. Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)
The t-value is: 1.943
We rounded down to the nearest person in the interval because we don't want to over estimate. It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate. It's better to use 28 and underestimate a little when considering customer flow.
