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2 years ago

I need help A. B. C. D.

Mathematics

2 answers:

koban [17]2 years ago

5 0

Answer:

$x \leqslant 3$

Third answer is correct.

Step-by-step explanation:

$2(4 + 2x) \geqslant 5x + 5 \\ 8 + 4x \geqslant 5x + 5 \\ 8 - 5 \geqslant 5x - 4x \\ = 3 \geqslant x$

hope this helps you

Sedaia [141]2 years ago

3 0

Answer:

$x\le 3$

Step-by-step explanation:

$2(4+2x)\ge 5x+5$

$2(4)+2(2x)\ge 5x+5$

$8+4x\ge 5x+5$

$8-5\ge 5x-4x$

$3\ge 1x$

$x\le 3$

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Desiree works 28 hours per week. She has a monthly income of $120 from investments. Desiree also plays in a band one night a wee

Oksi-84 [34.3K]

So hmmm let's see
she has a monthly income of 120 from investments, now, there are 12 months in a year, so her yearly income from investments are 120*12 or
$1440

she plays on a band, and makes 200 a week, now, there are 52 weeks in a year, so her yearly income from band playing is 200 * 52, or
$10400

her total annual income is 49696, now, if we subtract the band and investment income, we'd be left over with only what comes from her job payrate
so 49696 - 1440 - 10400 is 37856

so, she makes from her job, $37856 annually

now, she only works 28 hours weekly, how much is that yearly? well, 52 weeks in a year, she works 28*52 hours a year, let us divide 37856 by that

37856 ÷ ( 28 * 52) well, it ends up as 26

so, her hourly payrate is $26 per hour

now, she wants to ask for a raise, to make 51880 annually

well, if we check the difference of 51880 and 49696, that'd leave us with the difference in pay, or the raise annual amount

51880 - 49696 = 2184

ok, so she wants $2184 annually more from her work
how much is that in the hours she works annually? well 2184 ÷ ( 28 * 52)

7 0

2 years ago

Read 2 more answers

A random sample of 20 individuals who graduated from college five years ago were asked to report the total amount of debt (in $)

Gekata [30.6K]

Answer:

a. As college debt increases current investment decreases.

b. Y= 68778.2406 - 1.9112X

Every time the college debt increases one dollar, the estimated mean of the current investments decreases 1.9112 dollars.

c. There is a significant linear relationship between college debt and current investment because the P-value is less than 0.1.

d. Y= $59222.2406

e. R²= 0.9818

Step-by-step explanation:

Hello!

You have the information on a random sample of 20 individuals who graduated from college five years ago. The variables of interest are:

Y: Current investment of an individual that graduated from college 5 years ago.

X: Total debt of an individual when he graduated from college 5 years ago.

To see the relationship between the information about the debt and the investment is it best to make a scatterplot with the sample information.

As you can see in the scatterplot (attachment) there is a negative relationship between the current investment and the debt after college, this means that the greater the debt these individuals had, the less they are currently investing.

The statement that best describes it is: As college debt increases current investment decreases.

The population regression equation is Y= α + βX +Ei

To develope the regression equation you have to estimate alpha and beta:

a= Y[bar] -bX[bar]

a= 44248.55 - (-1.91)*12829.70

a= 68778.2406

b= $\frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }$

b= $\frac{9014653088-\frac{(256594)(884971)}{20} }{4515520748-\frac{(256594)^2}{20} }$

b= -1.9112

∑X= 256594

∑X²= 4515520748

∑Y= 884971

∑Y²= 43710429303

∑XY= 9014653088

n= 20

Means:

Y[bar]= ∑Y/n= 884971/20= 44248.55

X[bar]= ∑X/n= 256594/20= 12829.70

The estimated regression equation is:

Y= 68778.2406 - 1.9112X

Every time the college debt increases one dollar, the estimated mean of the current investments decreases 1.9112 dollars.

The hypotheses to test if there is a linear regression between the two variables are two tailed:

H₀: β = 0

H₁: β ≠ 0

α: 0.01

To make this test you can use either a Student t or the Snedecor's F (ANOVA)

Using t=<u> b - β </u>=<u> -1.91 - 0 </u>= -31.83

Sb 0.06

The critical region and the p-value for this test are two tailed.

The p-value is: 0.0001

The p-value is less than the level of signification, the decision is to reject the null hypothesis.

Using the

$F= \frac{MSTr}{MSEr}= \frac{4472537017.96}{4400485.72} =1016.37$

The rejection region using the ANOVA is one-tailed to the right, and so is the p-value.

The p-value is: 0.0001

Using this approach, the decision is also to reject the null hypothesis.

The conclusion is that at a 1% significance level, there is a linear regression between the current investment and the college debt.

The correct statement is:

There is a significant linear relationship between college debt and current investment because the P-value is less than 0.1.

To predict what value will take Y to a given value of X you have to replace it in the estimated regression equation.

Y/X=$5000

Y= 68778.2406 - 1.9112*5000

Y= $59222.2406

The current investment of an individual that had a $5000 college debt is $59222.2406.

To estimate the proportion of variation of the dependent variable that is explained/ given by the independent variable you have to calculate the coefficient of determination R².

$R^2= \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{sumY^2-\frac{(sumY)^2}{n} }$

$R^2= \frac{-1.9112^2[4515520748-\frac{(256594)^2}{20} ]}{43710429303-\frac{(884971)^2}{20} }$

R²= 0.9818

This means that 98.18% of the variability of the current investments are explained by the college debt at graduation under the estimated regression model: Y= 68778.2406 - 1.9112X

I hope it helps!

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2 years ago

Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins

alexira [117]

Answer: the answer will be the letter A

( l + w )

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2 years ago

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A professional writer decides to judge the value of her laptop by the number of times she presses

shusha [124]

Answer:

D.)

15040000 <= k <=19840000

Step-by-step explanation:

V = 1200 -0.00002k

Value V after one year falls in the range of $803.20 and $899.20.

Let's substract these values from 1200.

1200-803.20=396.80

1200-899.20=300.80

So it means that

0.00002k= 396.80

And

0.00002k= 300.80

0.00002k= 396.80

K= 396.80/0.00002

K= 19840000

And

0.00002k= 300.80

K = 300.80/0.00002

K= 15040000

So range is between

15040000 <= k <=19840000

7 0

2 years ago

Susie has 20 pieces of candy in a bag: 6 mint sticks, 5 jelly treats, and 9 fruit tart chews. If she eats one piece every 9 minu

motikmotik

Answer:

Step-by-step explanation:

7 fruit tart chews. If he eats one piece every 10 minutes, what is the probability his first two pieces will be a jelly treat and a mint stick? ... First you add all the candies together to get 20 in the bag 2+11+7=20 jelly treat: ... Paul has a bag with 6 mint sticks, 9 jelly treats, and 5 fruit tart chews. If he eats one ...

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2 years ago