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2 years ago

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A body of mass 80kg was lifted vertically through a distance of 5.0 metres. Calculate the work done on the body. ( Acceleration

due to gravity g=10ms²)

2 answers:

tamaranim1 [39]2 years ago

4 0

Answer:

80×5×10=4000J

so therefore, the work done on the body was 4000J

Murljashka [212]2 years ago

3 0

Answer:

4000N

Step-by-step explanation:

Check the attachment

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Company A charges $331.35 per week for a compact car with unlimited miles. Company B charges $175 per week plus $0.53 per mile,

Vladimir [108]

Answer:

Company A is a better deal than Company B for the number of miles greater than 295 miles

Step-by-step explanation:

Let

y ----> the charge per week in dollars

x ----> the number of miles

we have

<em>Company A</em>

$y=331.35$ -----> equation A

<em>Company B</em>

$y=0.53x+175$ -----> equation B

Solve the system by substitution

Equate equation A and equation B and solve for x

$331.35=0.53x+175$

$0.53x=331.35-175\\0.53x=156.35\\x=295\ mi$

For x=295 miles the charge in Company A and Company B is the same

therefore

Company A is a better deal than Company B for the number of miles greater than 295 miles

5 0

2 years ago

What are the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4? (–13,

Lana71 [14]

I added a screenshot of the complete question.

<u><em>Answer:</em></u>

(-7, -1)

<u><em>Explanation:</em></u>

<u>The formulas given to calculated the x and y coordinates are as follows:</u>

$x = (\frac{m}{m+n})(x_{2}-x_{1}) + x_{1}\\\\y = (\frac{m}{m+n})(y_{2}-y_{1}) + y_{1}$

<u>Let's define the variables used:</u>

(x₁ , y₁) are the coordinates of the first point while (x₂ , y₂) are the coordinates of the second point.

<u>We are given that the segment is directed from J to K, therefore:</u>

First point is J ..........> (x₁ , y₁) is (-15, -5)

Second point is K ....> (x₂ , y₂) is (25, 15)

m and n defined the portion of the partitioned segment (JE : EK). It is given that this ratio is 1:4. <u>Therefore:</u>

m = 1 and n = 4

<u>Finally, let's substitute with these variables in the equations as follows:</u>

$x = (\frac{1}{1+4})(25-(-15)) + (-15) = -7\\\\y = (\frac{1}{1+4})(15-(-5)) + (-5) = -1$

Based on the above, the coordinates of point E are (-7, -1)

Hope this helps :)

8 0

2 years ago

Read 2 more answers

Imagine that you have plotted many data points on an xy-plane. Your points seem to align into a clear best-fit line. Do you thin

sattari [20]

It depends really. If you stay close to the present, then predicting future results isn't too bad. The further you go out, the more unpredictable things get. This is because the points may deviate from the line of best fit (aka regression line) as time wears on. Of course, it also depends on what kind of data we're working with. Some pairs of variables are naturally going to correlate very strongly together. An example would be temperature versus ice cream sales.

5 0

2 years ago

At her job, Jessie earns $9.50 per hour.

Stolb23 [73]

Answer:

9.50h ≤ 460

Step-by-step explanation:

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2 years ago

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A financial advisor tells you that you can make your child a millionaire if you just start saving early. You decide to put an eq

Blababa [14]

Answer:

$12159 per year.

Step-by-step explanation:

If I invest $x each year at the simple interest of 7.5%, then the first $x will grow for 35 years, the second $x will grow for 34 years and so on.

So, the total amount that will grow after 35 years by investing $x at the start of each year at the rate of 7.5% simple interest will be given by

$x( 1 + \frac{35 \times 7.5}{100}) + x( 1 + \frac{34 \times 7.5}{100}) + x( 1 + \frac{33 \times 7.5}{100}) + ......... + x( 1 + \frac{1 \times 7.5}{100})$

= $35x + \frac{x \times 7.5}{100} [35 + 34 + 33 + ......... + 1]$

= $35x + \frac{x \times 7.5}{100} [\frac{1}{2} (35) (35 + 1)]$

{Since sum of n natural numbers is given by $\frac{1}{2} (n)(n + 1)$ }

= 35x + 47.25x

= 82.25x

Now, given that the final amount will be i million dollars = $1000000

So, 82.25x = 1000000

⇒ x = $12,158. 05 ≈ $12159

Therefore. I have to invest $12159 per year. (Answer)

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2 years ago