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grigory [225]
2 years ago
8

Imagine that you have plotted many data points on an xy-plane. Your points seem to align into a clear best-fit line. Do you thin

k this best-fit line can help you make predictions about future data? Explain your answer, and give one or more examples to support it.
Mathematics
1 answer:
sattari [20]2 years ago
5 0

It depends really. If you stay close to the present, then predicting future results isn't too bad. The further you go out, the more unpredictable things get. This is because the points may deviate from the line of best fit (aka regression line) as time wears on. Of course, it also depends on what kind of data we're working with. Some pairs of variables are naturally going to correlate very strongly together. An example would be temperature versus ice cream sales.

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The parabola y=x^2y=x 2 y, equals, x, start superscript, 2, end superscript is reflected across the xxx-axis and then scaled ver
kramer

ANSWER

The equation of the new parabola is

y =  - 5 {x}^{2}

EXPLANATION

The given parabola has equation:

y =  {x}^{2}

If this parabola is reflected in the x-axis, its equation becomes :

y =  -  {x}^{2}

When this parabola is scaled vertically by a factor of 5, the equation becomes,

y =  - 5 {x}^{2}

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15,000 blue trout were released into the Meherrin River for a scientific study. The function, f(x) = 15,000 (98)x , represents t
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Answer:

I'm guessing you mean f(x)=15,000(9/8)^x. If this is what you mean, the population would increase by about 12,000 (12030.4870605 to be exact).

Step-by-step explanation:

Starting equation: f(x)=15,000(9/8)^x

You can clean up the 9/8 to be 1.125

Now what you want to do is find the answer to (9/8)^5 which is 1.8020324707

Next multiply 1.8020324707 by 15,000 and you get 27030.4870605

Finally 27,030.4870605 - 15,000 gives you 12030.4870605. Which means that the population increased by about 12,000.

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Answer:

P(paid) =  10/26

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