A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year
2 answers:
Answer:
The required equation is .
Step-by-step explanation:
Consider the provided information.
The Initial value of poster = $ 18
After 1 year amount of increase = $ 20.70
With the rate of 15% = 0.15
Let future value is y and the number of years be x.
Now verify this by substituting x=1 in above equation.
Which is true.
Hence, the required equation is .
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Answer:
Option C) The average contents of all bottles of juice in the population, which is 473 mL
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 473 mL
Sample mean, = 472 mL
Sample size, n = 30
Sample standard deviation, σ = 0.2
First, we design the null and the alternate hypothesis
Representation of
is the population parameter that represents the population mean.
Thus, for the given situation represents:
Option C) The average contents of all bottles of juice in the population, which is 473 mL
Answer:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solutio to the problem
Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:
Where and
For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.
The definition of sample mean is given by:
If we solve for the total T we got:
For this case then the expected value and variance are given by:
And the deviation is just:
So then the distribution for the total would be also normal and given by:
And we want this probability:
And we can use the z score formula given by: