Answer:
C. (18+4)
Step-by-step explanation:
The answer on ed
Let’s look at the permutations of the letters “ABC.” We can write the letters in any of the following ways:
ABC
ACB
BAC
BCA
CBA
CAB
Since there are 3 choices for the first spot, two for the next and 1 for the last we end up with (3)(2)(1) = 6 permutations. Using the symbolism of permutations we have:

. Note that the first 3 should also be small and low like the second one but I couldn’t get that to look right.
Now let’s see how this changes if the letters are AAB. Since the two As are identical, we end up with fewer permutations.
AAB
ABA
BAA
To make the point a bit better let’s think of one A are regular and one as bold
A.
ABA and AB
A look different now because we used bold for one of the As but if we don’t do this we see that these are actual the same. If they represented a word they would be the same exact word.
So in this case the formula would be

. We use 2! In the denominator because there are 2 repeating letters. If there were three we would use 3!
Hopefully, this is enough to let you see that the answer is A. The number of permutations is limited by the number of items that are identical.
Answer:
Step-by-step explanation:
y = 5x + 20
Start at (0, 20).
Then plot a point at (1, 25).
The line should be going through points (2, 30), (3, 35), (4, 40), (5, 45), etc.
For every time the x number goes up, the y number goes up 5 times for the 5%.
Answer:
4585.8 feet
Step-by-step explanation:
If we draw the triangle, the opposite side to 3° angle would be "10" less than total height of 250 because Nick is 10 feet above water level, so that side will be:
250 - 10 = 240
The hypotenuse of the triangle is the length of line of sight. We can call this "x".
So, using trigonometric ratio of sine (opposite/hypotenuse), we can write:

Now, we cross multiply and solve for x, line of sight length:

Answer:
(a) 

(b)

Step-by-step explanation:
(a)

Let u = π x
differentiating with respect to x
du = π dx

Putting the value of x and dx

[ c is an arbitrary constant]
Now putting the value of u
(b)

Let 
differentiating with respect to x

2du = dx
Putting the value of x and dx
=
=
Now putting the value of u
[ c is an arbitrary constant]