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2 years ago

5

Why did the paper rip when the student tried to stretch out the horizontal axis of his graph? Unscramble this letters to figure

it out: T, N, S, O, I, E, N, X

1 answer:

KIM [24]2 years ago

6 0

I would guess the answer to be Tension, if not for the extra 'X'....
or
Extension, if you add another 'E'...

You might be interested in

Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi

algol13

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x + 510y = 92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x + 510y = 92.25

x + 397y = 77.56

-------------------------------

0 + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y = 0.13----------------------------------(3)

Substituting (3) in (1)

x + 510(0.13) = 92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) = $\frac{54.95}{0.13}$

daytime minutes = 422.69

daytime minute $\approx 423$

3 0

2 years ago

Divide 42 in a ratio of 1:2:3

Vilka [71]

the ratio in which 42 should be divided is 1:2:3

the sum of the parts of the ratio is - 1 + 2 + 3 = 6

this means that there's a sum of 6 parts

so we need to find how much 1 part is equivalent to

if 6 parts are equivalent to 42

then 1 part is equivalent to - 42/6 = 7

so the ratio should be 1:2:3

1 part - 7

2 parts - 7 x 2 = 14

3 parts - 7 x 3 = 21

therefore 42 divided into 1:2:3 ratio is as follows

7 : 14 : 12

4 0

1 year ago

Read 2 more answers

Determine if each of the following sets is a subspace of ℙn, for an appropriate value of n. Type "yes" or "no" for each answer.

xxMikexx [17]

Answer:

1. Yes.

2. No.

3. Yes.

Step-by-step explanation:

Consider the following subsets of Pn given by

1.Let W1 be the set of all polynomials of the form $p(t)=at^2$ , where a is in ℝ.

2.Let W2 be the set of all polynomials of the form $p(t)=t^2+a$ , where a is in ℝ.

3. Let W3 be the set of all polynomials of the form $p(t)=at^2+at$ , where a is in ℝ.

Recall that given a vector space V, a subset W of V is a subspace if the following criteria hold:

- The 0 vector of V is in W.

- Given v,w in W then v+w is in W.

- Given v in W and a a real number, then av is in W.

So, for us to check if the three subsets are a subset of Pn, we must check the three criteria.

- First property:

Note that for W2, for any value of a, the polynomial we get is not the zero polynomial. Hence the first criteria is not met. Then, W2 is not a subspace of Pn.

For W1 and W3, note that if a= 0, then we have p(t) =0, so the zero polynomial is in W1 and W3.

- Second property:

W1. Consider two elements in W1, say, consider a,b different non-zero real numbers and consider the polynomials

$p_1 (t) = at^2, p_2(t)=bt^2$ .

We must check that p_1+p_2(t) is in W1.

Note that

$p_1(t)+p_2(t) = at^2+bt^2 = (a+b)t^2$

Since a+b is another real number, we have that p1(t)+p2(t) is in W1.

W3. Consider two elements in W3. Say $p_1(t) = a(t^2+t), p_2(t)= b(t^2+t)$ . Then

$p_1(t) + p_2(t) = a(t^2+t) + b(t^2+t) = (a+b) (t^2+t)$

So, again, p1(t)+p2(t) is in W3.

- Third property.

W1. Consider an element in W1 $p(t) = at^2$ and a real scalar b. Then

$bp(t) = b(at^2) = (ba)t^2)$ .

Since (ba) is another real scalar, we have that bp(t) is in W1.

W3. Consider an element in W3 $p(t) = a(t^2+t)$ and a real scalar b. Then

$bp(t) = b(a(t^2+t)) = (ba)(t^2+t)$ .

Since (ba) is another real scalar, we have that bp(t) is in W3.

After all,

W1 and W3 are subspaces of Pn for n= 2

and W2 is not a subspace of Pn.

6 0

2 years ago

A newly drilled water well produces 50,000 quarts of water per week. With no new water feeding the well, the production drops by

Sveta_85 [38]

Answer:

Total amount of water = 5,200,000

Step-by-step explanation:

Given:

water produced = 50,000 quarts of water per week

Production drop = 5% = 0.05 per year

Number of week in year = 52 week

Find:

Total amount of water

Computation:

Sum = a / r

a = 50,000 x 52

a = 2,600,000

Sum = a / [1-r]

Sum = 2,600,000 / 5%

Sum = 2,600,000 / 0.05

Total amount of water = 5,200,000

5 0

1 year ago

Greg has $2,571.68 in his bank account and makes automatic monthly rental payments of $321.46 for a car loan. If he stops making

Anestetic [448]

Answer:

8 months

Step-by-step explanation:

Given that:

Amount of money present in the bank account = $2,571.68

Automatic monthly rental payments for car loan = $321.46

Any deposits in the bank account are stopped.

To find:

The number of months taken so that the automatic payments make the value of the account as zero?

Solution:

Let the number of months taken to make the value of the account zero = $m$ months

To find the value of $m$ , we need to divide the total amount initially present in bank account with the monthly rental payment amount.

Therefore, the equation to find the value of $m$ , can be written as:

$m = \dfrac{2571.68}{321.46}$

On solving the above equation, we get the value as following:

$\bold{m=8}$ months

5 0

2 years ago