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2 years ago

Which represents a side length of a square that has an area of 450 square inches?

2 answers:

7 0

<span>I have been a high school/jr high math teacher for the past 13 years. I am happy to explain how to proceed with this problem.
A square is a figure where ALL sides are exactly the same. The find the area of the square you would multiply one side times another side. You would be multiplying a number times itself. So if you already have the area, you would take the square root to find your answer. When you do, you end up with 21.21 square inches rounded to the nearest hundredth.</span>

ElenaW [278]2 years ago

3 0

Answer:

A!!!!!!

15 sqrt 2 in

Step-by-step explanation:

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The data in the table above was compiled by a new pet information website from a random survey of users with Basset Hounds and W

pshichka [43]

Answer:

An adult Welsh Corgi is always going to be shorter than an adult Basset Hound.

Step-by-step explanation:

That's what I think because the Basset Hound is 13.8 in. in height right? So he's two inches taller if we round up both numbers. Basset hound would be 14 and welsh corgi would be 11....................okay im not sure i give up but it's either

"An adult Welsh Corgi is always going to be shorter than an adult Basset Hound."

"Basset hounds tend to be a little over two inches taller than Welsh Corgis, but have a higher variability in height.

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2 years ago

For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How

natulia [17]

<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let $e$ the cost of the exam hours

Let $w$ be the cost of the workshop hours

Let $l$ be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

$e=2w$ equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

$w=2l$ equation (2)

Finally, we also know that 3hr exams 24hr workshops and 12hr lectures cost $528, so:

$3e+24w+12l=528$ equation (1)

Now, lets find the value of $l$ :

Step 1. Solve for $l$ in equation (3)

$3e+24w+12l=528$

$12l=528-3e-24w$ equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

$12l=528-3e-24w$

$12l=528-3(2w)-24w$

$12l=528-6w-24w$

$12l=528-30w$ equation (5)

Step 3. Replace equation (2) in equation (5) and solve for $l$

$12l=528-30w$

$12l=528-30(2l)$

$12l=528-60l$

$72l=528$

$l=\frac{528}{72}$

$l=\frac{22}{3}$

$l=7.33$

Cost of lectures = $7.33 per hour

3 0

2 years ago

Read 2 more answers

Alonso went to the market with \$55$55dollar sign, 55 to buy eggs and sugar. He knows he needs a package of 121212 eggs that cos

eduard

Answer:

2.75+11.50S $\leq$ 55

Step-by-step explanation:

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2 years ago

A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 6 grams and the amo

borishaifa [10]

Let x represent number of bracelets and y represent number of necklaces.

We have been given that a jeweler made 7 more necklaces than bracelets. This means that number of necklaces will be $x+7$ . We can represent this information in an equation as: