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Alla [95]
2 years ago
5

Peter and Jacob are members of different video game libraries. Peter pays a membership fee of $45, and he pays $6 for every vide

o game he rents. The following function shows the total amount of money, y, in dollars, that Jacob pays for renting x number of video games. y=5x+25.
How many more dollars does Peter pay for a membership fee than Jacob.

OPTIONS:
A)$11
B)$20
C)$25
D)$45
Mathematics
2 answers:
4vir4ik [10]2 years ago
6 0

in the equation for Jacob the membership fee would be the 25

 so if Peter is paying 45, 45-25 = 20

 Peter is paying $20 more

leonid [27]2 years ago
4 0

Answer:

B) $20

Step-by-step explanation:

Given,

The membership fee for peter = $ 45,

Also, the function that represents the total amount of money, y, in dollars, that Jacob pays for renting x number of video games is,

y=5x+25

Since, the membership must be free from the variable (x),

Thus, the membership fee for jacob = $ 25,

The difference between the membership of Peter and jacob = $ 45 - $ 25 = $ 20,

Hence, Peter pays $ 20 more membership fee than that of Jacob.

Option 'B' is correct.

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The quantities xxx and yyy are proportional. xxx yyy 888 222 161616 444 323232 888 Find the constant of proportionality (r)(r)le
Tcecarenko [31]

Answer:

Step-by-step explanation:

1/4

4 0
2 years ago
If f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)?
alexandr1967 [171]

Answer:

<h2>The domain is all real values of x except \frac{4}{5}.</h2>

Step-by-step explanation:

The function, f(x) = \frac{x - 3}{x}.

g(x) = 5x - 4.

Hence, (f circle g) (x) = \frac{5x - 4 - 3}{5x - 4}.

We need to find the domain of (f circle g) (x) .

The domain means the set of values of x, for which we will get a real value of (f circle g) (x).

The function will not give a real value when, 5x - 4 = 0 that is x = \frac{4}{5}.

Hence, the domain of the function will be all real values of x rather than \frac{4}{5}.

5 0
2 years ago
Read 2 more answers
You bought $2000 worth of stocks in 2012. The value of the stocks has been decreasing by 10% each year. What will your stock be
goblinko [34]

Answer:

that is the solution to the question

7 0
2 years ago
Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure.
Alona [7]

Answer:

Step-by-step explanation:

Hello!

The monitoring system warn the driver when the tire pressure of the vehicle is 28% below target pressure.

Be X: target tire pressure of a certain car (pounds per square inch)

a)

X= 28 psi

If the monitoring system will warn the driver when the pressure is 28% below the target pressure: X-0.28X

First step, you have to calculate the 28% of 28psi

28*0.28= 7.84

Second step, is to subtract the calculated 28% to the target pressure:

28 - 7.84= 20.16

The TPMS will trigger a warning at 20.16 psi.

b)

If X~N(μ;σ²)

μ= 28psi (since the average is on target, then the target pressure for the car will be the average value of the distribution)

σ= 3psi

P(X≤20.16)

The standard normal distribution is tabulated. Any value of any random variable X with normal distribution can be "converted" by subtracting the variable from its mean and dividing it by its standard deviation.

So to calculate each of the asked probabilities, you have to first, "transform" the value of the variable to a value of the standard normal distribution Z, then you use the standard normal tables to reach the corresponding probability.

Z= (X-μ)/σ= (20.16-28)/3= -2.61

Now you have to look for the corresponding value of probability using the Z-table. Since the value is negative you have to the use the left entry of the Z-table, in the first column you'll find the integer and first decimal of the value -2.6- and in the first row you'll find the second decimal value -.-1

The value of probability that corresponds to -2.61 is:

P(Z≤-2.61)= 0.005

c)

You have to calculate the probability of inspecting a tire at random and it being inflated within recommended range, symbolically this is:

P(30≤X≤26)= P(X≤30)-P(X≤26)

Calculate both Z values:

Z= (30-28)/3= 0.67

Z= (26-28)/3= -0.67

P(Z≤0.67)-P(Z≤-0.67)= 0.749 - 0.251= 0.498

The probability of the tire being inflated within recommended inflation range is 0.498.

I hope this helps!

5 0
2 years ago
Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average
enot [183]
Then, 15 - x is the distance ran in the second part.
The time, t1, for the first part is t1 = xmi / 8mi/h
The time, t2, for the second part is t2 = (15 - x)mi / 20mi/h
The total time is t1 + t2 = 1.125 h
Then x/8 + (15 - x) / 20 = 1.125
To solve for x, multiply both sides by 40 (this is the least common multiple)
5x + 30 - 2x = 45
3x = 15

to find x divide: 15/3=5

And 15 - x = 10 mi.
First part:
Speed: 8mi/h
Distance: 5 mi
Time: 5mi/8mi/h = 5/8 h = 37.5 minutes
Second part
Speed: 20 mi/h
Distance: 10 mi
Average speed: 15mi/1.125h =13.33 mi/h
Distance: 15mi
Time: 1.125 h = 67.5 minutes 
7 0
2 years ago
Read 2 more answers
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