Answer:
We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.
Step-by-step explanation:
Let's first list the percentage compositions of each fertilizer type:
<u>Vigoro Ultra Turf:</u>
Nitrogen (N) = 29 kg
Phosphoric Acid (P2O5) = 3 kg
Potash (K2O) = 4 kg
<u>Parkers Premium</u>
Nitrogen (N) = 18 kg
Phosphoric Acid (P2O5) = 25 kg
Potash (K2O) = 6 kg
We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:
x = Vigoro Ultra turf (one bag)
y = Parkers Premium (one bag)
29x + 18y = 217 -Equation 1
3x + 25y = 115 -Equation 2
4x + 6y = 44 -Equation 3
Solving for x and y, we get:
x = 5
y = 4
This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.
The numbers start from the top
The intersection between the curves are
3, 0
0, 3
The volume of the solids is obtained by
V = ∫ π [ (4 - (y-1)²)² - (3 - y)²] dy with limits from 0 to 3
The volume is
V = 108π/5 or 67.86
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
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