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WINSTONCH [101]
2 years ago
11

Jack, Jill, and Bill each carried a 48 ounce bucket full of water down the hill.  By the time they reached the bottom, Jack's bu

cket was only 3/4 full, Jill's was 2/3 full, and bill's was 1/6 full.  How much water did they spill altogether on their way down the hill?

Mathematics
2 answers:
kaheart [24]2 years ago
7 0
Altogether they spilled about 70 ounces

SCORPION-xisa [38]2 years ago
7 0
3/4 of 48 = 36
2/3 of 48 = 32
1/6 of 48 =  8
They Spilled  76 ounces of water altogether!
Happy to Help!
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Evaluate 3/2y-3+ 5/3z when y= 6 and z=3
wolverine [178]
1 plus 3 equals 4
Your answer is 4

3 0
2 years ago
Read 2 more answers
A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

7 0
2 years ago
Select the correct answer from each drop-down menu.
kompoz [17]

Answer: B has greater spread than A.

Step-by-step explanation:

Since we have given that

Set A: {38, 12, 23, 48, 55, 16, 18}

Range of A = Highest - Lowest

Range of A =  55  -  12

Range of A = 43

Set B:{44, 13, 24, 12, 56}

Range of B = Highest - Lowest

Range of B =    56      -     12

Range of B =       44

Since Range of B is more than range of A.

Hence, B has greater spread than A.

6 0
2 years ago
"Our customer retention rate has decreased 10% from last quarter's goal of 250 consumers retained. We need to increase our curre
Lorico [155]
1. multiply 250 by 10% (250 * .1= 25)
2. Then subtract 25 from 250 (250 -25= 225)
2. Then multiply 225 by 16% (225 * .16 = 36)
3. Add 225 + 36 = 261. 
4. 261 is your final answer
6 0
2 years ago
To test the impact performance of a 10 cm thick gymnastics mat, a 20 kg cylindrical
denis23 [38]

Answer:

A)196J

B)-208J

C)3467J

Step-by-step explanation:

We are given that a 20 kg cylindrical  mass is dropped onto the mat from a height of 1 m above the mat. During the impact,  the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to  only 4 cm thick.

So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m

a)

Using Conservations of energy

Potential energy at the top = Kinetic energy at the point before touching the surface

Kinetic energy = mgh= 20 \times 9.8 \times 1 = 196 J

b)

Work done  by the mat do to stop the fall of the cylinder =-mg(h+0.06)=-20 \times 9.8(1+0.06)=-208 J

C)

Work done=\text{Average force} \times \text{ Compression of mat}

208=F \times 0.06

F=3467J

8 0
2 years ago
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