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2 years ago

Use the diagram to find the measure of each of the angles.

Mathematics

2 answers:

just olya [345]2 years ago

8 0

Angle AQB is x = 90

Angle ASB is x = 90

Angle ALB is x = 90

Angle ATB is x = 90

Angle ARB is x = 90

<span>BWD is x < 90</span>

Elis [28]2 years ago

7 0

Answer:

If an angle is inscribed in a semicircle, it will be half the measure of a semicircle (180°), that is, measuring 90 degrees.

According to the given diagram,

Q, S, L, T, R and W are the points of the circumference of the circle having center O,

Also, AB is the diameter of the given circle,

∠AQB, ∠ASB, ∠ALB, ∠ATB, ∠ARB and ∠AWB are the angles on the semicircle,

Thus, by the above property,

m∠AQB = 90°

m∠ASB = 90°

m∠ALB = 90°

m∠ATB = 90°

m∠ARB = 90°

m∠AWB = 90°

If m∠BWD = x

Since, By the diagram,

m∠BWD < m∠AWD

⇒ m∠BWD < 90°

⇒ x < 90°

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