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KATRIN_1 [288]
2 years ago
15

On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The numb

er b varies directly with the number a. For example b = 2a equals negative 2 and StartFraction 3 Over 4 EndFraction. when a = –2a equals negative 2 and StartFraction 3 Over 4 EndFraction.. Which equation represents this direct variation between a and b?
Mathematics
1 answer:
vfiekz [6]2 years ago
5 0

Answer:

b

Step-by-step explanation:

Guest
1 year ago
actually its A
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Marvin has a coupon the discount is the rental of a full-size car by $25 they decide to buy insurance for each day if the cost i
ipn [44]

Answer: Marvin needs approximately 19 days to rent the car.

Step-by-step explanation:

Since we have given that

Amount Marvin get on a discount coupon = $25

She decided to buy insurance for each day.

Let the number of days be x

cost of insurance = $465

According to question, it becomes,

25x=465\\\\x=\frac{465}{25}\\\\x=18.6\\\\x=19\ days

Hence, Marvin needs approximately 19 days to rent the car.

7 0
2 years ago
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You wanted to join a booth fair, and you are aiming to get a profit that is twice as
sashaice [31]

You wanted to join a booth fair, and you are aiming to get a profit that is twice as  your capital. Using the given information, your sample plan may be as follows:

Product                   Organic skincare products for women

Description             An organic skincare cream and soap that brightens

                                 and moisturizes your skin.

Goal                          To provide anti-aging skin for women and

                                  maintaining  their skin body.

Capital                      15000

Fixed Cost                  7000

Variable Cost             8000

Profit function            300(a) = 450a - 150a

To prove that the profit function will yield twice the capital.

This profit function: 300(y) = 450y - 150y will help achieve twice profit as your capital.

Profit function = revenue function r(y) - cost function c(y)

300(y) = 450y - 150y

where;

  • y = no of units produced and sold.
  • p = profit sold per unit

Cost function C(y) = fixed cost + (variable cost) × (amount of unit sold)

Assumption:

Cost function C(y) = 7000 + (80 × 100)

Cost function C(y) = 7000 + 8000

Cost function C(y) = 15000

Revenue function R(y) = price per revenue sold × no of sold units

R(y) = 450 × 100

R(y) = 45000

∴

Profit function = 45000 - 15000

Profit function = 30000

Therefore, can conclude that the profit function is revenue function r(y) - cost function c(y).

Hence the formula:

Profit function = revenue function r(y) - cost function c(y)   (Proved)

Learn more about Profit function here:

brainly.com/question/16866047?referrer=searchResults

8 0
1 year ago
1) The cost of constructing a path 5 m broad inside the boundary of a square lawn at Rs 36.25 per sq. metre is Rs 90625. What is
Svetach [21]

Let , side lawn is a.

Area of boundary is :

A=4\times5\times a\\\\A=20a\ m^2

Now, total cost is given by :

T=20a\times 36.25\\\\90625=725a\\\\a=125\ m

Area left is :

A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2

Price to empty space with turfs is :

P=A'\times 20\\\\P=13125\times 20\\\\P=262500

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.

Hence, this is the required solution.

3 0
2 years ago
In the xy-plane, point E has coordinates (4,5) and point O has coordinates (0,0). Which of the following is an equation of the l
Paha777 [63]

Answer:

D

Step-by-step explanation:

You can plug in the given x and y values into the equations and see which one works for both of them.

D works for both of them:

5 = 5/4(4)

0 = 5/4(0)

6 0
2 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0
2 years ago
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