Answer:
a) 20%
b) 40%
c) Mean = 62.5 seconds; Variance = 52.083 seconds
Step-by-step explanation:
The time it takes a hematology cell counter to complete a test on a blood sample is continuously distributed over the period of 50 to 75 seconds with probability f(x) = 0.04.
a) The percentage of tests require more than 70 seconds is:

b)The percentage of tests that require less than one minute (60 seconds) is:

c) The mean and variance of a continuous distribution are determined by:

Mean = 62.5 seconds.
Variance = 52.083 seconds.
Answer:
D.)
15040000 <= k <=19840000
Step-by-step explanation:
V = 1200 -0.00002k
Value V after one year falls in the range of $803.20 and $899.20.
Let's substract these values from 1200.
1200-803.20=396.80
1200-899.20=300.80
So it means that
0.00002k= 396.80
And
0.00002k= 300.80
So
0.00002k= 396.80
K= 396.80/0.00002
K= 19840000
And
0.00002k= 300.80
K = 300.80/0.00002
K= 15040000
So range is between
15040000 <= k <=19840000
Answer:
The answer is below
Step-by-step explanation:
The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.
The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at (
) and B(
) is given by the formula:

If point Q is at (
) and S at (
) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

Let us assume Q(−9,4) and S(7,−4)

I'm pretty sure the answer will be 6/10
Hope this helps, best of luck, terribly sorry if I'm wrong if I am my apologies
~Animaljamissofab ♥
Answer: a) 0.25, b) 0.78, c) 0.71
Step-by-step explanation:
Since we have given that
Number of employees in marketing = 4
Number of employees in management = 7
We need to hire committee of 3 people.
a) Find the probability that the committee has exactly 2 employees from marketing.
So, Probability becomes

b) Find the probability that the committee has at least one employee from marketing.

c) Find the probability that the committee has at most one employee from management.

Hence, a) 0.25, b) 0.78, c) 0.71