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Serhud [2]
1 year ago
14

Apply the distributive property to factor out the greatest common factor.75+20=

Mathematics
2 answers:
Oksi-84 [34.3K]1 year ago
4 0

Answer:

5(15+4)

Step-by-step explanation:

The greatest common factor is the greatest number that will divide two values. We have two values 75 and 20. Each has numbers which multiply together to give the number. We need to find the highest value or most in common they share. Each has the factors:

75: 1,3,5,15,25, 75

20: 1, 2, 4, 5, 10, 20

Both have 5 and this is the GCF. So we write the expression int he form 5(___+___). We divide each term by 5 to find the corresponding factor.

75/5= 15

20/5=4

5(15+4)


stiks02 [169]1 year ago
4 0

Answer:

5(15+4)

Step-by-step explanation:

5

15+

and (4)

add them all together.

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The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations. 

For ex:
2 - (8 + 3)  here, the 8 and 3 have to be grouped together before doing the subtraction.

Any addition problem without parentheses can be used for one where the grouping doesn't matter
3 0
1 year ago
It costs $3 to bowl a game and $2 for shoe rental. a. Write an expression for the total cost (in dollars) of $g$ games. Expressi
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Answer: a. Total cost = 3g+2

b. The total cost of 8 games is $26.

Step-by-step explanation:

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Total cost = (Cost to bowl a game) x (Number of games)+ (Shoe rental charge )

Let g= number of games, then the expression to find the total cost will be :

Total cost = 3g+2

To find the total cost of 8 games, put g=8, we get

Total cost = 3(8)+2

= 24+2 = $26

Therefore , the total cost of 8 games is $26.

7 0
1 year ago
From a survey of coworkers you find that 32​% of 150 have already received this​ year's flu vaccine. An approximate 98​% confide
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Answer:

a) Narrower

b) Narrower

c) Wider            

Step-by-step explanation:

We are given the following in the question:

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98​% confidence interval: (0.231​, 0.409​)

Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

​a) Sample size had been 600 instead of 150​

If we increase the sample size, thus the standard error of the interval decreases.

Since the standard error decreases, the confidence interval become narrower.

b) Confidence level had been 90​% instead of 98​%

As the confidence level increases, the confidence interval becomes narrower. This is due to a smaller value of z-statistic at 90% confidence level.​

c) Confidence level had been 99​% instead of 98​%

As the confidence level increases, the width of the confidence interval increases and the confidence interval become wider. This is because of a larger value of z-statistic at 99% confidence interval.

4 0
1 year ago
Biologists conducted a study to investigate the flying velocity of mosquitoes both before and after feeding. The following scatt
Lesechka [4]

Answer:

It represents a mosquito that flew very fast after feeding relative to all other mosquitoes.

Step-by-step explanation:

The point is unusual because the velocity of the mosquito is substantially greater than all other velocities and is probably an outlier.

4 0
1 year ago
Find the solutions of the congruence 12x2 + 25x ≡ 10 (mod 11). [Hint: Show the congruence is equivalence to the congruence 12x2
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Answer:23.89x67

Step-by-step explanation:

5 0
1 year ago
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