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2 years ago

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The image of trapezoid PQRS after a reflection across Line W Y is trapezoid P'Q'R'S'. 2 trapezoids are shown. Line W Y is the li

ne of reflection. Line segment R R prime has a midpoint at point Z. Line segment S S prime has a midpoint at point X. What is m? 45º 90º 180º 270º

2 answers:

RoseWind [281]2 years ago

3 0

Answer:

90

Step-by-step explanation:

harina [27]2 years ago

3 0

Answer:

90

Step-by-step explanation:

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A triangular flag has an area of 187.5 square inches. The base of the flag measures 25 inch How tall is the triangular flag?

djyliett [7]

To find the height, you would do the area divided by the base, or in this case,187.5 / 25 which equals 7.5 inches. Hope this helped!

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2 years ago

Which graph is defined by the function given below? y=(x-2)(x+5)

Igoryamba

Step 1: Foil to get y=x^2+3x-10

Step 2: The C of the equation is -10, which is the y-intercept (so the answer is graph A)

Just to check, you can find the x intercepts

x-2=0

x=2

x+5=0

x=-5

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2 years ago

An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection of

Anna [14]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

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2 years ago

Elisa is 9 years old. When 7 is subtracted from Krista’s age and 1/4 of the difference is taken , the result is equal to Elisa’s

garri49 [273]

Answer:

43

Step-by-step explanation:

just go backwards so multiply 9 by 4

36

then add 7

43

then to check go 43-7

36-1/4

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2 years ago

Exercise 5.6.6: Selecting a committee of senators. About A country has two political parties, the Demonstrators and the Repudiat

krok68 [10]

Answer:

There are 4,148,350,734,528 ways

Step-by-step explanation:

We have

44 senators which are Demonstrators.
56 senators which are Repudiators.

(a) How many ways are there to select a committee of 10 senate members with the same number of Demonstrators and Repudiators?

We want to choose 5 Demonstrators and 5 Repudiators. The number of ways to do this is ${44} \choose {5}$ and $56 \choose 5$ respectively. Therefore, the number of ways to select the committee is given by:

${{44}\choose {5}} \times {{56}\choose{5}}=\frac{44!}{39!5!}\times\frac{56!}{51!5!}=\frac{44!56!}{51!39!5!5!}=\frac{44\times43\times42\times41\times40\times56\times55\times54\times53\times52}{5!5!}=\\\\=\frac{44\times43\times42\times41\times8\times56\times11\times54\times53\times52}{4!4!}= \frac{11\times43\times42\times41\times2\times56\times11\times54\times53\times52}{3!3!}=\\\\\frac{11\times43\times14\times41\times2\times56\times11\times18\times53\times52}{2!2!}=$

$11\times43\times14\times41\times28\times11\times18\times53\times52=4,148,350,734,528$

(b) Suppose that each party must select a speaker and a vice speaker. How many ways are there for the two speakers and two vice speakers to be selected?

<u>If the speaker and vice speaker are chosen between all senators:</u> In this case, the answer will be

$44\times43\times56\times55=5,827,360.$

This is because there are (in the case of Demonstrators) 44 possibilities to choose an speaker and after choosing one, there would be 43 possibilities to choose a vice speaker. The same situation happens in the case of Repudiators.

<u>If the speaker and vice speaker are chosen between the committee:</u> In this case, the answer will be

$5\times4\times5\times4=400$ .

3 0

2 years ago